用于在字符串中查找模式的 Javascript 正则表达式，排除可能的前面单词匹配

Question

变量中有一个文字/文本字符串：

var copypaste, replaced;
var verbdb = ["keep","know","enjoy"];
var arrayLength = verbdb.length;

for (var i = 0; i < arrayLength; i++) {
    copypaste = "One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah.";

    replaced = copypaste.replace(RegExp("[^let]? first_name " + verbdb[i] + "(\s|\.)","g")," first_name " + verbdb[i] + "_object_s\$1");
}

---

我试图从replaced变量中得到的是仅当 first_name 前面有let一词时才排除。

“first_name keep_object_s 晚上醒来的原因之一，是等等等等。试试这个，让 first_name 知道，看看等等等等。记住 first_name enjoy_object_s 受到挑战，等等等等。”;

---

所以在这个例子中：

1. 第一个模式匹配（保持）并替换为添加的_object_s ，
2. 由于“让”这个词，第二个模式不匹配（知道），所以没有替换
3. 第三个模式 MATCHES (enjoy) 并替换为添加的_object_s 。

Answer 1

你可以试试这个：

(?:\b)(?!let)(?=\w+\sfirst_name\s+(know|keep|enjoy))(\w+ \w+)\s+(\w+)

解释

 const regex = /(?:\\b)(?!let)(?=\\w+\\sfirst_name\\s+(know|keep|enjoy))(\\w+ \\w+)\\s+(\\w+)/g; const str = `One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah`; const subst = `$2 _object_s`; const result = str.replace(regex, subst); console.log(result);