用於在字符串中查找模式的 Javascript 正則表達式，排除可能的前面單詞匹配

Question

變量中有一個文字/文本字符串：

var copypaste, replaced;
var verbdb = ["keep","know","enjoy"];
var arrayLength = verbdb.length;

for (var i = 0; i < arrayLength; i++) {
    copypaste = "One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah.";

    replaced = copypaste.replace(RegExp("[^let]? first_name " + verbdb[i] + "(\s|\.)","g")," first_name " + verbdb[i] + "_object_s\$1");
}

---

我試圖從replaced變量中得到的是僅當 first_name 前面有let一詞時才排除。

“first_name keep_object_s 晚上醒來的原因之一，是等等等等。試試這個，讓 first_name 知道，看看等等等等。記住 first_name enjoy_object_s 受到挑戰，等等等等。”;

---

所以在這個例子中：

1. 第一個模式匹配（保持）並替換為添加的_object_s ，
2. 由於“讓”這個詞，第二個模式不匹配（知道），所以沒有替換
3. 第三個模式 MATCHES (enjoy) 並替換為添加的_object_s 。

Answer 1

你可以試試這個：

(?:\b)(?!let)(?=\w+\sfirst_name\s+(know|keep|enjoy))(\w+ \w+)\s+(\w+)

解釋

 const regex = /(?:\\b)(?!let)(?=\\w+\\sfirst_name\\s+(know|keep|enjoy))(\\w+ \\w+)\\s+(\\w+)/g; const str = `One of the reasons first_name keep waking up at night, is blah blah blah. Try this, let first_name know and see blah blah blah. Remember that first_name enjoy being challenged and blah blah blah`; const subst = `$2 _object_s`; const result = str.replace(regex, subst); console.log(result);