在joda时间API中比较两个日期的问题

Question

我有一个下面的程序来比较两个日期。

我得到的时间戳是date1和currentTimestamp，在这里我只需要比较日期而不是时间value。但是下面的程序总是返回-1。（value）

timestamp date1 = "2017-01-20 14:51:30.091"  // i get this from service call in this format

SimpleDateFormat dateFormat = new SimpleDateFormat(DEFAULT_TIMESTAMP_FORMAT);
Calendar calendar = Calendar.getInstance();
String formattedDate = dateFormat.format(calendar.getTime());
java.util.Date currentDate = dateFormat.parse(formattedDate);
java.sql.Timestamp currentTimestamp = new java.sql.Timestamp(currentDate.getTime());

int value = DateTimeComparator.getDateOnlyInstance().compare(date1 , currentTimestamp );

如何只比较日期，而不考虑时间。 请帮我。

更新：

我更改为以下代码

timestamp date1 = "2017-01-20 14:51:30.091"  // i get this from service call in this format
 LocalDate localDate = new LocalDate();
int value = DateTimeComparator.getDateOnlyInstance().compare(date1 , localDate );

这给了我一个错误，说“ java.lang.IllegalArgumentException：未找到类型为org.joda.time.LocalDate的即时转换器”

Answer 1

要比较joda没有时间的DateTime ，您有2个选项：

• 将DateTime转换为LocalDate 。
• 使用DateTimeComparator.getDateOnlyInstance

例如：

@Test
public void compareJodaTime() {
    DateTimeFormatter dateTimeFormatter = DateTimeFormat.forPattern("yyyy-MM-dd HH:mm:ss.SSS");

    String today = "2017-01-20 14:51:30.091";  
    String tomorrow = "2017-01-21 14:51:30.091"; 

    DateTime now = DateTime.now();

    Assert.assertThat(now.toLocalDate().compareTo(DateTime.parse(today, dateTimeFormatter).toLocalDate()), Matchers.is(0));
    Assert.assertThat(now.toLocalDate().compareTo(DateTime.parse(tomorrow, dateTimeFormatter).toLocalDate()), Matchers.is(-1));
    Assert.assertThat(now.toLocalDate().isEqual(DateTime.parse(today, dateTimeFormatter).toLocalDate()), Matchers.is(true));
    Assert.assertThat(now.toLocalDate().isBefore(DateTime.parse(tomorrow, dateTimeFormatter).toLocalDate()), Matchers.is(true));


    Assert.assertThat(DateTimeComparator.getDateOnlyInstance().compare(now, DateTime.parse(today, dateTimeFormatter)), Matchers.is(0));
    Assert.assertThat(DateTimeComparator.getDateOnlyInstance().compare(now, DateTime.parse(tomorrow, dateTimeFormatter)), Matchers.is(-1));
}

Answer 2

这不是乔达的解决方案...

使用：Apache库'commons-lang3-xxjar'（DateUtils）

@Test
public void testCompare() {
 Date current = new Date();
 Date previous = DateUtils.addHours(DateUtils.addDays(new Date(), -1),5);
 assertEquals(1,DateUtils.truncatedCompareTo(current,previous,Calendar.DATE));
 assertEquals(0,DateUtils.truncatedCompareTo(current,current,Calendar.DATE));
 assertEquals(-1,DateUtils.truncatedCompareTo(previous,current,Calendar.DATE));
}

Answer 3

您可以使用JodaTime尝试以下代码： DateTime date1 = DateTime.parse("2017-01-20 14:51:30.091", DateTimeFormat.forPattern("YYYY-MM-dd HH:mm:ss.SSS")); DateTime now = new DateTime(); int value = DateTimeComparator.getDateOnlyInstance().compare(date1 , now); DateTime date1 = DateTime.parse("2017-01-20 14:51:30.091", DateTimeFormat.forPattern("YYYY-MM-dd HH:mm:ss.SSS")); DateTime now = new DateTime(); int value = DateTimeComparator.getDateOnlyInstance().compare(date1 , now);