[英]How to remove any html tags within a specific pattern in beautifulsoup
<p> A <span>die</span> is thrown \\(x = {-b \\pm <span>\\sqrt</span> {b^2-4ac} \\over 2a}\\) twice. What is the probability of getting a sum 7 from both the throws? </p>
在上面的 html 中,我只需要删除 "\\(tags\\)" 中的标签,即\\(x = {-b \\pm <span>\\sqrt</span> {b^2-4ac} \\over 2a}\\\\)
。 我刚刚开始使用beautifulsoup 有什么办法可以用beautifulsoup 实现吗?
我想出了我的问题的解决方案。 希望它可以帮助其他人。 请随时给我建议以改进代码。
from bs4 import BeautifulSoup
import re
html = """<p>
A
<span>die</span>
is thrown \(x = {-b \pm
<span>\sqrt</span>
{b^2-4ac} \over 2a}\) twice. What is the probability of getting a sum 7 from
both the throws?
</p> <p> Test </p>"""
soup = BeautifulSoup(html, 'html.parser')
mathml_start_regex = re.compile(r'\\\(')
mathml_end_regex = re.compile(r'\\\)')
for p_tags in soup.find_all('p'):
match = 0 #Flag set to 1 if '\(' is found and again set back to 0 if '\)' is found.
for p_child in p_tags.children:
try: #Captures Tags that contains \(
if re.findall(mathml_start_regex, p_child.text):
match += 1
except: #Captures NavigableString that contains \(
if re.findall(mathml_start_regex, p_child):
match += 1
try: #Replaces Tag with Tag's text
if match == 1:
p_child.replace_with(p_child.text)
except: #No point in replacing NavigableString since they are just strings without Tags
pass
try: #Captures Tags that contains \)
if re.findall(mathml_end_regex, p_child.text):
match = 0
except: #Captures NavigableString that contains \)
if re.findall(mathml_end_regex, p_child):
match = 0
输出:
<p>
A
<span>die</span>
is thrown \(x = {-b \pm
\sqrt
{b^2-4ac} \over 2a}\) twice. What is the probability of getting a sum 7 from
both the throws?
</p>
<p> Test
</p>
在上面的代码中,我搜索了所有 'p' 标签,它返回bs4.element.ResultSet 。 在第一个 for 循环中,我迭代结果集以获取单独的“p”标签,并在第二个 for 循环中使用 . children生成器迭代“p”标签子项(包含可导航的字符串和标签)。 每个 'p' 标签的孩子都被搜索 '\\(',如果找到匹配设置为 1,如果迭代到匹配的孩子时为 1 然后使用replace_with删除特定孩子中的标签,最后匹配是找到 '\\)' 时设置为零。
光靠美汤是拿不到子串的。 您可以将正则表达式与它一起使用。
from bs4 import BeautifulSoup
import re
html = """<p>
A
<span>die</span>
is thrown \(x = {-b \pm
<span>\sqrt</span>
{b^2-4ac} \over 2a}\) twice. What is the probability of getting a sum 7 from
both the throws?
</p>"""
soup = BeautifulSoup(html, 'html.parser')
print re.findall(r'\\\(.*?\)', soup.text, re.DOTALL)
输出:
[u'\\(x = {-b \\pm \n \\sqrt\n {b^2-4ac} \\over 2a}\\)']
正则表达式:
\\\(.*?\) - Get substring from ( to ).
如果你想去掉换行符和空格,你可以这样做:
res = re.findall(r'\\\(.*?\)', soup.text, re.DOTALL)[0]
print ' '.join(res.split())
输出:
\(x = {-b \pm \sqrt {b^2-4ac} \over 2a}\)
字符串周围的 HTML 包装器:
print BeautifulSoup(' '.join(res.split()))
输出:
<html><body><p>\(x = {-b \pm \sqrt {b^2-4ac} \over 2a}\)</p></body></html>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.