使用多个分隔符提取文本

Question

我有分隔符A和B的字符串列表：

L = ['sgfgfqds A aaa','sderas B ffff','eeee','sdsdfd A rrr']

并需要：

L1 = [['aaa'], ['ffff'], ['eeee'], ['rrr']] 

我试过用：

L1 = [re.findall(r'(?<=A)(.*)$', inputtext) for inputtext in L]
print (L1)

但是，它返回以下内容：

[[' aaa'], [], [], [' rrr']] 

如何获得所需的输出？

Answer 1

您可以使用re.split在'A'或'B'上打破字符串：

>>> L1 = [re.split(r'[AB] *', inputtext)[-1] for inputtext in L]
>>> L1
['aaa', 'ffff', 'eeee', 'rrr']

Answer 2

没有regex替代建议。

[[i] for i in ' '.join(L).split(' ') if i.count(i[0]) == len(i) and len(i) > 1]

结果

 [['aaa'], ['ffff'], ['eeee'], ['rrr']]

Answer 3

即使找不到分隔符，您也可以使用split返回列表的事实。

 L1 = [[x.split(' A ')[-1].split(' B ')[-1]] for x in L]

Answer 4

如果您希望这不仅仅适用于A或B，您可以使用

>>> L = ['sgfgfqds A aaa','sderas B ffff','eeee','sdsdfd A rrr', 'lasjd X gggggg']
>>> L1 = [re.split(r'[A-Z] *', inputtext)[-1] for inputtext in L]
>>> print(L1)
['aaa', 'ffff', 'eeee', 'rrr', 'gggggg']

Answer 5

for a in L:
   if 'A' in a or 'B' in a:
       clist = a.split()
       for c in clist:
           if c[::-1] == c:
               if c == 'A' or c == 'B':
                    pass
                else:
                  #print "c1",c
                   result.append([c])
            else:
                 pass
   else:
       result.append([a])

   print result