[英]Python: How to filter a list of dictionaries to get all the values of one key
我在python中有一个字典列表:
thedata = [{'date': '2002-02', 'data': 2.0},
{'date': '2002-03', 'data': 2.0017}...]
如何列出“数据”值?
[2.0, 2.0017...]
我试过了:
justFigures = list(filter(lambda x: x["data"], thedata))
您可以尝试这样:
thedata = [{'date': '2002-02', 'data': 2.0},
{'date': '2002-03', 'data': 2.0017}]
print([a['data'] for a in thedata])
输出:
[2.0, 2.0017]
我会使用列表理解
In [1]: thedata = [{'date': '2002-02', 'data': 2.0},
{'date': '2002-03', 'data': 2.0017}]
In [2]: just_figures = [ d['data'] for d in thedata ]
In [3]: just_figures
Out[3]: [2.0, 2.0017]
thedata = [{'date': '2002-02', 'data': 2.0},
{'date': '2002-03', 'data': 2.0017}]
# back to your own way, lambda
# py 2
print map(lambda a : a["data"], thedata)
# py 3
print (list(map(lambda a : a["data"], thedata)))
>>> [2.0, 2.0017]
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