如何计算表中的多个列并使用php显示它们

Question

我有一些带有一些列的表（见下图）：

我的表：

我想计算那些列中的值（使用一些过滤器（即1.20和1.50之间的best_bets），使用一些过滤器（即，介于1.20和1.50之间）中有多少“ok”和“no”，我们在列中超过05，超过15等）并使用php显示它们

现在，我可以使用以下代码对列进行计数：

    $result=mysql_query("SELECT count(over15) as total from risultati WHERE over15 = 'OK' AND best_bets >= 1.15 AND best_bets <= 1.50");
$data=mysql_fetch_assoc($result);
echo $data['total'];

但我想为更多的专栏做这件事

问候

编辑：我试过这种方式，但它不起作用：

$result=mysql_query("SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O");
$data=mysql_fetch_assoc($result);
echo $data['OK_15'];
echo $data['OK_25'];
echo $data['OK_35'];
echo $data['OK_45'];

edit2：我也尝试过另一种方式，但没有：

$result=mysql_query("SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O");



while ($row = mysql_fetch_assoc($result)) 
{
    echo $row['OK_05'];
    echo $row['OK_15'];
    echo $row['OK_25'];
    echo $row['OK_35'];
    echo $row['OK_45'];

}

Answer 1

使用条件聚合：

SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O    -- or whatever restrictions you want

此方法允许您在单个查询中收集所有年龄列的统计信息，而将列检查“确定”限制为一个查询中的单个列。