如何計算表中的多個列並使用php顯示它們

Question

我有一些帶有一些列的表（見下圖）：

我的表：

我想計算那些列中的值（使用一些過濾器（即1.20和1.50之間的best_bets），使用一些過濾器（即，介於1.20和1.50之間）中有多少“ok”和“no”，我們在列中超過05，超過15等）並使用php顯示它們

現在，我可以使用以下代碼對列進行計數：

    $result=mysql_query("SELECT count(over15) as total from risultati WHERE over15 = 'OK' AND best_bets >= 1.15 AND best_bets <= 1.50");
$data=mysql_fetch_assoc($result);
echo $data['total'];

但我想為更多的專欄做這件事

問候

編輯：我試過這種方式，但它不起作用：

$result=mysql_query("SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O");
$data=mysql_fetch_assoc($result);
echo $data['OK_15'];
echo $data['OK_25'];
echo $data['OK_35'];
echo $data['OK_45'];

edit2：我也嘗試過另一種方式，但沒有：

$result=mysql_query("SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O");



while ($row = mysql_fetch_assoc($result)) 
{
    echo $row['OK_05'];
    echo $row['OK_15'];
    echo $row['OK_25'];
    echo $row['OK_35'];
    echo $row['OK_45'];

}

Answer 1

使用條件聚合：

SELECT SUM(CASE WHEN over05 = 'OK' THEN 1 ELSE 0 END) AS OK_05,
       SUM(CASE WHEN over15 = 'OK' THEN 1 ELSE 0 END) AS OK_15,
       SUM(CASE WHEN over25 = 'OK' THEN 1 ELSE 0 END) AS OK_25,
       SUM(CASE WHEN over35 = 'OK' THEN 1 ELSE 0 END) AS OK_35,
       SUM(CASE WHEN over45 = 'OK' THEN 1 ELSE 0 END) AS OK_45
FROM risultati
WHERE best_bets BETWEEN 1.15 AND 1.5O    -- or whatever restrictions you want

此方法允許您在單個查詢中收集所有年齡列的統計信息，而將列檢查“確定”限制為一個查詢中的單個列。