申诉问题

Question

我在通过Safari通过链接打开应用程序时遇到问题（以后将来自我自己的应用程序）如果该应用程序已打开，则没有问题。 如果应用未打开，则通过URL打开时会崩溃。 我已经学会了，那是因为我调用的appdelegate 2种不同的方法- didFinishLaunchingWithOptions和open url

打开应用程序时，通过打开的URL打开我没有问题，但是如果我通过关闭的应用程序中的URL打开，则应用程序崩溃。 我了解到， didFinishLauchingWithOptions url参数可能为null，但是如何对其进行测试。 当我同时在模拟器和iPad上关闭应用程序时，XCode终止连接

编辑 -在Sachin Vas评论后，现在可以调试了。 在XCode调试中获取此内容-但无法扩展有效负载

我的功能看起来像这样

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    self.window = UIWindow(frame: UIScreen.main.bounds)
    let storyBoard : UIStoryboard = UIStoryboard(name: "Main", bundle:nil)

    let nav = storyBoard.instantiateViewController(withIdentifier: "HomeNavController") as! UINavigationController
    let home = storyBoard.instantiateViewController(withIdentifier: "HomeViewController") as! HomeViewController



    if let url = launchOptions?[UIApplicationLaunchOptionsKey.url] as? NSURL {
        if let itemid = getQueryStringParameter(url: url.absoluteString!, param: "itemid"){
            NetworkService().getSpecificExercise(id: itemid) { response, error in
                let exercise = response! as VoiceExercise
                let vc = storyBoard.instantiateViewController(withIdentifier: "ExerciseViewController") as! ExerciseViewController
                vc.exercise = exercise
                switch exercise.type {
                case "STRENGTH":
                    vc.exercisetype = .strength
                case "RANGE":
                    vc.exercisetype = .range
                case "COMBINED":
                    vc.exercisetype = .combined
                default:
                    print(exercise.type)
                }
                nav.pushViewController(vc, animated: false)
                self.window?.rootViewController = nav
                //self.window?.makeKeyAndVisible()

            }
            return true
        }
    }else{
        //nav.pushViewController(home, animated: true)
        self.window?.rootViewController = home
        self.window?.makeKeyAndVisible()
    }

    nav.pushViewController(home, animated: true)
    self.window?.rootViewController = nav
    self.window?.makeKeyAndVisible()
    return true
}

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
    if let itemid = getQueryStringParameter(url: url.absoluteString, param: "itemid"){
        NetworkService().getSpecificExercise(id: itemid) { response, error in
            let exercise = response! as VoiceExercise
            let vc = storyBoard.instantiateViewController(withIdentifier: "ExerciseViewController") as! ExerciseViewController
            vc.exercise = exercise
            switch exercise.type {
            case "STRENGTH":
                vc.exercisetype = .strength
            case "RANGE":
                vc.exercisetype = .range
            case "COMBINED":
                vc.exercisetype = .combined
            default:
                print(exercise.type)
            }
            self.window?.rootViewController = vc
            self.window?.makeKeyAndVisible()

        }
        return true
    }else{
        return false
    }

}

Answer 1

您可以检查url的主机不为null，以及是否让url如下所示

if url.host == nil
{
  return true;
}

if let sUrl = url
 {
   urlString = url.absoluteString
 }

希望能帮助到你！

更新

func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
    if let launchOptions = launchOptions {
        if #available(iOS 9.0, *) {
            if let url = launchOptions[UIApplicationLaunchOptionsKey.url] as? UIApplicationShortcutItem {
                print("url: \(url)")
            }
        }
    }
    return true
}