PHP每周日期范围，带有特定的开始和结束日期

Question

嗨，我已经有了日期范围的结果，但是如何使日期范围从每个星期四开始到星期三结束。 谢谢你的帮助 ：）

$week_range = '';
for ($i = 0; $i <= 4; $i++) {
    $k = $i - 1;

    $ymd_week_range = date('Y-m-d', strtotime("-$i week")) . ',' . date('Y-m-d', strtotime("-$k week -1 day"));

    $day_from = date('j', strtotime("-$i week"));
    $day_to = date('j', strtotime("-$k week -1 day"));
    $month_to = date('M', strtotime("-$i week"));
    $month_from = date('M', strtotime("-$k week -1 day"));
    $year_to = date('Y', strtotime("-$i week"));
    $year_from = date('Y', strtotime("-$k week -1 day"));

    $weeks[$ymd_week_range] = "$month_from $day_from-$day_to, $year_to";   
}



Array
    (
        [2017-03-16,2017-03-22] => Mar 16-22, 2017
        [2017-03-09,2017-03-15] => Mar 9-15, 2017
        [2017-03-02,2017-03-08] => Mar 2-8, 2017
        [2017-02-23,2017-03-01] => Mar 23-1, 2017
        [2017-02-16,2017-02-22] => Feb 16-22, 2017
    )

所以今天是星期四，所以它是正确的。 但是，如果今天是星期五，那么结果是错误的。 如果今天是星期五，那么我想要上面的正确结果。 错误的结果是：

Array
        (
            [2017-03-17,2017-03-23] => Mar 17-23, 2017
            [2017-03-10,2017-03-16] => Mar 10-16, 2017
            [2017-03-03,2017-03-09] => Mar 3-9, 2017
            [2017-02-24,2017-03-02] => Mar 24-2, 2017
            [2017-02-17,2017-02-23] => Feb 17-23, 2017
        )

Answer 1

看到使用date()和strtotime()很痛苦。 使用DateTime()及其关联的类可以使此操作更容易理解。

在下面的示例中，我使用相对日期/时间格式，该格式允许我将星期四指定为结束日期。 然后，我返回六个星期，以开始日期为间隔一个星期。 然后，我遍历它们并将它们放入数组中。 我反转数组并打印出来。

$dates    = [];
$end      = new DateTimeImmutable('Thursday');
$start    = $end->modify('-6 weeks');
$interval = new DateInterval('P1W');
$period   = new DatePeriod($start, $interval, $end);
foreach ($period as $date) {
    $wednesday = $date->modify('Wednesday');
    $dates[] = sprintf('%s - %s%s', $date->format('D j M'), $wednesday->format('D j M'), PHP_EOL);
}
$dates = array_reverse($dates);
foreach ($dates  as $week) {
    echo $week;
}

演示

Thu 9 Mar - Wed 15 Mar
Thu 2 Mar - Wed 8 Mar
Thu 23 Feb - Wed 1 Mar
Thu 16 Feb - Wed 22 Feb
Thu 9 Feb - Wed 15 Feb
Thu 2 Feb - Wed 8 Feb

显然，您可以更改格式以适合您的需求。

Answer 2

您可以按照以下方式使用以下代码

<?php
$weeks = array();
$dayOfWeek = date('w');
$thurday = 4;
$diff = $thurday - $dayOfWeek;

for ($i = 0; $i <= 4; $i++) {
    $k = $i - 1;

    $ymd_week_range = date('Y-m-d', strtotime("-$i week")) . ',' . date('Y-m-d', strtotime("-$k week -1 day"));

    $day_from = date('j', strtotime("-$i week $diff day"));
    $day_to = date('j', strtotime("-$k week ".($diff - 1)." day"));
    $month_to = date('M', strtotime("-$i week $diff day"));
    $month_from = date('M', strtotime("-$k week ".($diff - 1)." day"));
    $year_to = date('Y', strtotime("-$i week $diff day"));
    $year_from = date('Y', strtotime("-$k week ".($diff - 1)." day"));

    $weeks[$ymd_week_range] = "$month_from $day_from-$day_to, $year_to";   
}

print_r($weeks);

Answer 3

这是我根据之前的错误代码修改后的正确答案：

<?php
for ($i = 0; $i <= 4; $i++) {
    $k = $i - 1;

    $from_text = strtotime("this week thursday -$i week");
    $to_text = strtotime("-$k week -1 day");

    $ymd_week_range = date('Y-m-d', $from_text) . ',' . date('Y-m-d', $to_text);

    $day_from = date('j', $from_text);
    $day_to = date('j', $to_text);

    $month_from = date('M', $from_text);
    $month_to = date('M', $to_text);

    $year_from = date('Y', $from_text);
    $year_to = date('Y', $to_text);

    $weeks[$ymd_week_range] = "$month_from $day_from - $month_to $day_to, $year_to";
}

我更改了笔记本电脑的日期并将其设置为明天（星期五），并且使用上面的代码现在结果正确：

结果：

Array
(
    [2017-03-16,2017-03-23] => Mar 16 - Mar 23, 2017
    [2017-03-09,2017-03-16] => Mar 9 - Mar 16, 2017
    [2017-03-02,2017-03-09] => Mar 2 - Mar 9, 2017
    [2017-02-23,2017-03-02] => Feb 23 - Mar 2, 2017
    [2017-02-16,2017-02-23] => Feb 16 - Feb 23, 2017
)