[英]How to add a method to an external class at runtime in Python?
PyGithub似乎不支持GitHub API调用来获取最新版本 。 我想知道是否可以在运行时为PyGithub添加一个方法来为我做这件事。
例如,现有代码具有以下方法:
# Repository.py
def get_releases(self):
"""
:calls: `GET /repos/:owner/:repo/releases <http://developer.github.com/v3/repos>`_
:rtype: :class:`github.PaginatedList.PaginatedList` of :class:`github.Tag.Tag`
"""
return github.PaginatedList.PaginatedList(
github.GitRelease.GitRelease,
self._requester,
self.url + "/releases",
None
)
我想将此添加到Repository.py类:
def get_latest_release(self):
return github.PaginatedList.PaginatedList(
github.GitRelease.GitRelease,
self._requester,
self.url + "/releases/latest",
None
)
我尝试了这个,但是收到一个错误:
# main.py
from types import MethodType
from github import Github
from github.Repository import Repository, github
def get_latest_release(self): ...
def main():
Repository.method = MethodType(get_latest_release, None, Repository)
g = Github(<my name>, <my password>)
org = g.get_organization(<name of org>)
repo = org.get_repo(<name of repository>)
release = repo.get_latest_release()
# AttributeError: 'Repository' object has no attribute 'get_latest_release'
是否可以在运行时添加此方法?
直接分配给Repository.get_latest_release
应该足够,例如:
Repository.get_latest_release = get_latest_release
如果您尝试分配给实例,则只需要MethodType
>>> import types
>>> class A(object):
... pass
>>> a = A()
>>> A.one = lambda self: 1
>>> a.two = types.MethodType(lambda self: 2, a)
>>> a.one(), a.two()
(1, 2)
在class
分配可用于class
所有实例的情况下, instance
分配不是:
>>> b = A()
>>> b.one()
1
>>> b.two()
AttributeError: 'A' object has no attribute 'two'
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