如何从php向python发送发布请求？

Question

我想从php向python发送发帖请求并获得答案，我编写了发送发帖的脚本

$url = 'http://localhost:8080/cgi-bin/file.py';
$body = 'hello world';
$options = array('method'=>'POST',
'content'=>$body,
'header'=>'Content-type:application/x-ww-form-urlencoded');
$context = stream_context_create(array('http' => $options));
print file_get_contents($url, false,$context);

我正在使用自定义python服务器

from http.server import HTTPServer, CGIHTTPRequestHandler
server_address = ("", 8080)
httpd = HTTPServer(server_address, CGIHTTPRequestHandler)
httpd.serve_forever()

和需要发布请求的python脚本

print('Content-type: text/html\n')
import cgi
form = cgi.FieldStorage()
text2 = form.getfirst("content", "empty")
print("<p>TEXT_2: {}</p>".format(text2))

然后我得到

write() argument must be str, not bytes\r\n'

如何解决？ PS对不起，我的英语不好

Answer 1

检查php的curl扩展名http://php.net/manual/zh/book.curl.php

<?php

$ch = curl_init();

curl_setopt($ch, CURLOPT_URL,"http://localhost:8080/cgi-bin/file.py");
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS,
        "postvar1=value1&postvar2=value2&postvar3=value3");

// in real life you should use something like:
// curl_setopt($ch, CURLOPT_POSTFIELDS, 
//          http_build_query(array('postvar1' => 'value1')));

// receive server response ...
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

$server_output = curl_exec ($ch);

curl_close ($ch);

Answer 2

您也可以使用类似guzzle的库，该库可能还需要使用其他一些功能。

用法示例可在以下其他答案中找到：

https://stackoverflow.com/a/29601842/6626810