Java：将字符串转换为在get中使用的url

Question

您好，我会直截了当地说，我正在尝试使用EditText输入在php url中使用，我希望该URL在运行时像thi一样。

http://www.free-map.org.uk/course/mad/ws/hits.php?artist=Oasis

所以我尝试了

 URL url = new URL("http://www.free-map.org.uk/course/mad/ws/hits.php?artist=",et1);

但是我得到了错误

这是我的代码的主要部分。

 class MyTask extends AsyncTask<Void,Void,String>
{
    EditText et1 = (EditText)findViewById(R.id.et1);

    public String doInBackground(Void... unused)
    {
        HttpURLConnection conn = null;
        try
        {
            URL url = new URL("http://www.free-map.org.uk/course/mad/ws/hits.php?artist=",et1);
            conn = (HttpURLConnection) url.openConnection();
            InputStream in = conn.getInputStream();
            if(conn.getResponseCode() == 200)
            {
                BufferedReader br = new BufferedReader(new InputStreamReader(in));
                String result = "", line;
                while((line = br.readLine()) !=null)
                    result += line;
                return result;
            }
            else
                return "HTTP ERROR: " + conn.getResponseCode();
        }
        catch(IOException e)
        {
            return e.toString();
        }
        finally
        {
            if(conn!=null)
                conn.disconnect();
        }
    }

Answer 1

我不确定您要做什么。

如果要将EditText的内容添加到URL，请尝试：

URL url = new URL("http://www.free-map.org.uk/course/mad/ws/hits.php?artist="+et1.getText().toString());

Answer 2

您不能在EditText后面加上String 。 您必须从EditText追加输入。

要从EditText获取输入，请使用-

EditText et1 = (EditText)findViewById(R.id.et1);
final String input = et1.getText().toString();
// then append it
URL url = new URL("http://www.free-map.org.uk/course/mad/ws/hits.php?artist="+input);