[英]Django Context Processor Login In Issue
我有一个登录系统:
def login(request):
title = "Login"
if request.user.is_authenticated():
return HttpResponseRedirect('/')
form = UserLoginForm(request.POST or None)
if request.POST and form.is_valid():
username = form.cleaned_data.get('username')
password = form.cleaned_data.get('password')
user = auth.authenticate(username=username, password=password)
if user:
auth.login(request, user)
return HttpResponseRedirect("/")# Redirect to a success page.
return render(request, 'accounts/login.html', {'title':title, 'form': form })
def logout(request):
auth.logout(request)
return HttpResponseRedirect('/accounts/login')
而且效果很好。 但是,当我尝试添加一个context_processor
它停止工作并给出以下错误:
Environment:
Request Method: GET
Request URL: http://localhost:8000/accounts/login/
Traceback:
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/handlers/exception.py" in inner
39. response = get_response(request)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
187. response = self.process_exception_by_middleware(e, request)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/handlers/base.py" in _get_response
185. response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/decorators.py" in _wrapped_view
149. response = view_func(request, *args, **kwargs)
File "/Users/andyxu/Documents/ece496-web/capstone/views.py" in login
22. return render(request, 'accounts/login.html', {'title':title, 'form': form })
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/shortcuts.py" in render
30. content = loader.render_to_string(template_name, context, request, using=using)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/loader.py" in render_to_string
68. return template.render(context, request)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/backends/django.py" in render
66. return self.template.render(context)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/base.py" in render
206. with context.bind_template(self):
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/contextlib.py" in __enter__
17. return self.gen.next()
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/template/context.py" in bind_template
236. updates.update(processor(self.request))
Exception Type: TypeError at /accounts/login/
Exception Value: 'NoneType' object is not iterable
这是我的context_processor.py:
from matchalgorithm.models import Profile
def add_variable_to_context(request):
if(request.user.id):
profile = Profile.objects.filter(user_id = request.user.id).first()
return {
'main_profile': profile
}
基本上,我只想检查用户是否有Profile
否则返回None
。 我想使用此变量传递到我的base.html
,该视图不会由任何视图呈现。 有趣的是,一旦我logged in
,它就可以正常工作!
谢谢
您的上下文处理器上的缩进似乎已关闭,它与您的描述不符。 我假设return
语句在if语句内,因为它与您的描述和回溯都匹配。
文档说(重点是我的):
上下文处理器具有一个非常简单的接口:这是一个Python函数,它接受一个参数,一个
HttpRequest
对象,并返回添加到模板上下文的字典。 每个上下文处理器必须返回一个字典。
因此,如果您不想在上下文中添加任何内容,则处理器必须返回一个空字典,而不是None
:
def add_variable_to_context(request):
if(request.user.id):
profile = Profile.objects.filter(user_id = request.user.id).first()
return {
'main_profile': profile
}
return {}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.