[英]PHP How to check if an array contains a pattern from another array
我正在寻找一个与in_array相同的替代函数,但也可以检查搜索项是否仅包含给定元素的一部分而不是整个元素:
当前正在使用以下脚本:
$attributes = array('dogs', 'cats', 'fish');
if (in_array($attributes, array('dog','cats','fishess'), true )) {
* does something for cats, but not for dogs and fish
because the function only checks if the given term is identical to the word in the array instead of only a part of the word *
}
我将如何构建我的up函数,使其传递只包含数组中单词部分的单词?
首选示例如下所示:
$words = array('fish', 'sharks');
if (*word or sentence part is* in_array($words, array('fishing', 'sharkskin')){
return 'your result matched 2 elements in the array $words
}
使用array_filter
和preg_grep
函数的解决方案:
$words = ['fish', 'sharks', 'cats', 'dogs'];
$others = ['fishing', 'sharkskin'];
$matched_words = array_filter($words, function($w) use($others){
return preg_grep("/" . $w . "/", $others);
});
print_r($matched_words);
输出:
Array
(
[0] => fish
[1] => sharks
)
请尝试以下代码:
<?php
$what = ['fish', 'sharks'];
$where = ['fishing', 'sharkskin'];
foreach($what as $one)
foreach($where as $other)
echo (strpos($other, $one)!==false ? "YEP! ".$one." is in ".$other."<br>" : $one." isn't in ".$other."<br>");
?>
希望对您有帮助=}
您可以使用:
array_filter($arr, function($v, $k) {
// do whatever condition you want
return in_array($v, $somearray);
}, ARRAY_FILTER_USE_BOTH);
此函数在数组$arr
的每个项目上调用一个您可以自定义的函数,在这种情况下,请检查您是否在另一个数组中
为什么不仅仅编写自己的代码/函数呢?
foreach ($item in $attributes) {
foreach ($item2 in array('dog','cats','fishess')) {
// Check your custom functionality.
// Do something if needed.
}
}
您可以看一下array_intersect ,但是它不会检查模式匹配(您已经提到了它吗?)
array_intersect()返回一个数组,其中包含所有自变量中存在的所有array1值。 请注意,密钥被保留。
foreach (array_intersects($attributes, array('dog','cats','fishess') {
// do something.
}
我会去:
$patterns = array('/.*fish.*/', '/.*sharks.*/');
$subjects = array('fishing', 'aaaaa', 'sharkskin');
$matches = array();
preg_replace_callback(
$patterns,
function ($m) {
global $matches;
$matches[] = $m[0];
return $m[0];
},
$subjects
);
print_r($matches); // Array ( [0] => fishing [1] => sharkskin )
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