从数组中获取价格最高的对象

Question

嗨，如何使用javascript获取价格最高的对象：

我有此代码，但效果不佳

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = 0;
for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber < item.Price) {
    biggestNumber = item;
  }
}
console.log(biggestNumber);

Answer 1

let highestPrice = Math.max.apply(null, array.map(e => e.Price));
let item = array.find(e => e.Price === highestPrice);

Answer 2

 var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}]; var maxIndex = 0; // assume the max is at 0 for(var i = 1; i < array.length; i++) { // for the rest of the objects in the array if(array[i].Price > array[maxIndex].Price) // if the current object is bigger than the assumed max maxIndex = i; // then this current object's index is the new maxIndex } var maxObject = array[maxIndex]; // max object is the object at maxIndex console.log(maxObject); 

Answer 3

您可以使用Array.prototype.reduce将整个数组“缩小”为一个值：价格最大的对象。

var itemWithHighestPrice = array.reduce(function(highest, item, index) {
    if (index === 0 || item.Price > highest.Price) {
        return item;
    }
    return highest;
}, {});

Answer 4

您必须将item.Price存储在maximumNumber中，而不是仅存储item中。

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = 0;
for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}
console.log(biggestNumber);

Answer 5

经典的方法与for声明 。

该建议将第一个元素作为临时结果，并使用结果检查数组的所有后续对象。 如果找到更大的Price ，则result更改为实际元素。

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }], result = array[0], // take the first element i; for (i = 1; i < array.length; i++) { // iterate from the second on if (array[i].Price > result.Price) { // check price, if a greater price found result = array[i]; // replace result with actual object } } console.log(result); 

或者您可以使用Array#reduce并在回调内部返回检查结果。

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }], result = array.reduce(function (a, b) { return a.Price > b.Price ? a : b; }, {}); console.log(result); 

与ES6相同

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }], result = array.reduce((a, b) => a.Price > b.Price ? a : b, {}); console.log(result); 

Answer 6

 var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}]; var biggestNumber = {Price:0}; array.forEach(function(obj){ if(obj.Price>biggestNumber.Price) biggestNumber=obj; }); console.log(biggestNumber); 

Answer 7

问题：

您的问题是，您将整个item对象存储在highestPrice变量中，然后尝试将Number与object进行比较。

解：

您应该只在item.Price Price变量中存储highestPrice并比较Price值，如下所示编辑代码：

var biggestNumber = 0;
for (var i = 0; i < array.length; i++) {
  var item = array[i];
  if (biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}

工作片段：

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }]; var biggestNumber = 0; for (var i = 0; i < array.length; i++) { var item = array[i]; if (biggestNumber < item.Price) { biggestNumber = item.Price; } } console.log(biggestNumber); 

注意：

如果希望将整个item作为结果，则只需比较两个对象的Price属性，就可以像这样更新第一个代码：

for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber.Price < item.Price) {
    biggestNumber = item;
  }
}