Get object from array with largest price

Question

Hi how to get object with largest Price using javascript:

I have this code but it doesn't work good

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = 0;
for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber < item.Price) {
    biggestNumber = item;
  }
}
console.log(biggestNumber);

Answer 1

let highestPrice = Math.max.apply(null, array.map(e => e.Price));
let item = array.find(e => e.Price === highestPrice);

Answer 2

 var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}]; var maxIndex = 0; // assume the max is at 0 for(var i = 1; i < array.length; i++) { // for the rest of the objects in the array if(array[i].Price > array[maxIndex].Price) // if the current object is bigger than the assumed max maxIndex = i; // then this current object's index is the new maxIndex } var maxObject = array[maxIndex]; // max object is the object at maxIndex console.log(maxObject); 

Answer 3

You can use Array.prototype.reduce to "reduce" your entire array into a single value: the object with the largest price.

var itemWithHighestPrice = array.reduce(function(highest, item, index) {
    if (index === 0 || item.Price > highest.Price) {
        return item;
    }
    return highest;
}, {});

Answer 4

You have to store item.Price in biggestNumber instead of just item.

var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}];
var biggestNumber = 0;
for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}
console.log(biggestNumber);

Answer 5

Classic approach with for statement .

This proposal takes the first element as temporary result and checks all following objects of the array with the result. If a greater Price is found, then result is changed to the actual element.

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }], result = array[0], // take the first element i; for (i = 1; i < array.length; i++) { // iterate from the second on if (array[i].Price > result.Price) { // check price, if a greater price found result = array[i]; // replace result with actual object } } console.log(result); 

Or you could use Array#reduce and return the result of the check inside of the callback.

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }], result = array.reduce(function (a, b) { return a.Price > b.Price ? a : b; }, {}); console.log(result); 

The same as above with ES6

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }], result = array.reduce((a, b) => a.Price > b.Price ? a : b, {}); console.log(result); 

Answer 6

 var array = [{Name: "blue",Price: 20},{Name: "red",Price: 10},{Name: "green",Price: 30}]; var biggestNumber = {Price:0}; array.forEach(function(obj){ if(obj.Price>biggestNumber.Price) biggestNumber=obj; }); console.log(biggestNumber); 

Answer 7

Problem:

Your problem is that you are storing the whole item object in your highestPrice variable, then you try to compare a Number with an object .

Solution:

You should store only the item.Price in your highestPrice variable and compare Price values, edit your code like this:

var biggestNumber = 0;
for (var i = 0; i < array.length; i++) {
  var item = array[i];
  if (biggestNumber < item.Price) {
    biggestNumber = item.Price;
  }
}

Working snippet:

 var array = [{ Name: "blue", Price: 20 }, { Name: "red", Price: 10 }, { Name: "green", Price: 30 }]; var biggestNumber = 0; for (var i = 0; i < array.length; i++) { var item = array[i]; if (biggestNumber < item.Price) { biggestNumber = item.Price; } } console.log(biggestNumber); 

Note:

If you want the whole item as result, you just need to compare the two objects Price property, update your first code like this:

for (var i = 0; i < array.length; i++){
    var item = array[i]
  if(biggestNumber.Price < item.Price) {
    biggestNumber = item;
  }
}