修改unique_together绑定表格django

Question

我正在尝试修改数据库的现有行，它来自中间表“ CharacterSkill”，具有唯一的共同约束：

models.py

class CharacterSkill(models.Model):
    character = models.ForeignKey(Character, on_delete=models.CASCADE)
    level = models.IntegerField(default=0)
    skill = models.ForeignKey(Skill, on_delete=models.CASCADE)
    class Meta:
        unique_together = ("character","skill")

我做了一个表格来更改级别，但是我无法保存表格，我从“字符”和“技能”两个字段中都收到了两条错误消息：

Select a valid choice. That choice is not one of the available choices.

你能帮上忙吗？ :)

我的表格：

class SkillCreateForm(forms.ModelForm):
    class Meta:
        model = CharacterSkill
        fields = ('skill','level','character',)

我的观点 ：

def skill_update(request,skillpk,instancepk):
    form = SkillCreateForm(request.POST)
    user = User.objects.get (id = request.user.id)
    instance = Character.objects.get (id = instancepk)
    skill = CharacterSkill.objects.get(id = skillpk)
    data = {'character' : instance,
        'skill' : skill.skill,
        'level' : skill.level,
        }
    if form.is_valid():
        form.save()
        return redirect('persomaker:skill_list', instance.id)
    else:
        form = SkillCreateForm(data)
        #form.fields['skill'].widget = HiddenInput()
        #form.fields['character'].widget = HiddenInput()
    return render(request, 'character/create_skill.html',
    {'instance':instance,
    'skill':skill,
    'form': form,})

Answer 1

基于一本书，我更改了将表单限制为使用instance的方式：

def skill_update(request,skillpk,instancepk):

    user = User.objects.get (id = request.user.id)
    instance = Character.objects.get (id = instancepk)
    skill = CharacterSkill.objects.get(id = skillpk)
    if request.method == "POST":
        form = SkillModifyForm(request.POST,instance = skill,)
        print (skill)
        if form.is_valid():
            form.save()
            return redirect('persomaker:skill_list', instance.id)
    else:
        form = SkillModifyForm(instance = skill,)
    return render(request, 'character/create_skill.html',
    {'instance':instance,
    'skill':skill,
    'form': form,})