[英]Concatenate a list of lists in a list Python3
我试过itertools,map()但我不知道这是怎么回事。 我有这个:
[['>Fungi|A0A017STG4.1/69-603 UP-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}', ['-', '-', '-', ... , '-', '-', '-', '-']],['>Fungi|A0A017STG4.1/69-603 UP1-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}', ['-', '-', '-', ... , '-', '-', '-', '-']],['>Fungi|A0A017STG4.1/69-603 UP12-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}', ['-', '-', '-', ... , '-', '-', '-', '-']]]
我要这个:
[['>Fungi|A0A017STG4.1/69-603 UP-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}','-', '-', '-', ... , '-', '-', '-', '-'],['>Fungi|A0A017STG4.1/69-603 UP1-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}','-', '-', '-', ... , '-', '-', '-', '-'],['>Fungi|A0A017STG4.1/69-603 UP10-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}','-', '-', '-', ... , '-', '-', '-', '-']]
我试过了
for i in x:
map(i,[])
和这个
import itertools
a = [["a","b"], ["c"]]
print list(itertools.chain.from_iterable(a))
请赐教!
必须有更好的Pythonic解决方案,但您可以使用:
n = []
for x in your_list:
temp_list = [x[0]]
[temp_list.append(y) for y in x[1]]
n.append(temp_list)
print(n)
输出:
[['>Fungi|A0A017STG4.1/69-603 UP-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}', '-', '-', '-', Ellipsis, '-', '-', '-', '-'], ['>Fungi|A0A017STG4.1/69-603 UP1-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}', '-', '-', '-', Ellipsis, '-', '-', '-', '-'], ['>Fungi|A0A017STG4.1/69-603 UP12-domain-containing protein {ECO:0000313|EMBL:EYE99555.1}', '-', '-', '-', Ellipsis, '-', '-', '-', '-']]
简单的oneliner可以做到:
[sum(x, []) for x in yourlist]
note sum(x,[])相当慢,因此,对于严重的列表合并,请使用更多乐趣,并使用快速讨论的快速列表合并技术进行讨论。
例如,简单的两个衬板速度更快
import itertools
map(list, (map(itertools.chain.from_iterable, yourlist)))
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.