我可以将不同类型的参数传递给同一函数吗？

Question

我有一个功能：

/*This function spawns a GameObject randomly at another GameObject's position and it takes 3 arguments:
Argument 1. type GameObject: the game object that will be spawned.
         2. type Transform[]: the GameObject will be spawned at this Transform position.
         3. type float: the distance that the camera must travel before the GameObject will be spawned. */
void SpawnPylon(GameObject whatSpawn, Transform[] whereSpawn, float spawnDistance)
{
    bool hasSpawnedPylon = false;

    if (currPosition != (int)transform.position.z)
    {
        if ((int)transform.position.z % spawnDistance == 0)
        {
            if (!hasSpawnedPylon)
            {
                //this makes the GameObject spawn randomly
                spawnIndex = Random.Range (0, spawnPoints.Length);
                //This is instantiationg the GameObject
                Instantiate (whatSpawn, whereSpawn [spawnIndex].position, whereSpawn [spawnIndex].rotation);
                //this makes shore that the GameObject is not spawned multiple times at aproximetley the same position.
                currPosition = (int)transform.position.z;
            }
        }
    }
    else
    {
        hasSpawnedPylon = false;
    }
}

如您所见，该函数采用3个类型的参数： GameObject ， Transform[]和float 。

如何使我可以提供类型Transform而不是Transform[] 。

更具体地说，如何使函数接受更多不同类型的参数，而实际上不需要传递每个参数：

因此，例如，我可以使用不同的类型来调用函数，例如：

`SpawnPylon(GameObject ,Transform[] ,float`)

然后执行以下操作：

SpawnPylon(GameObject ,Transform ,float)

或这样做：

SpawnPylon(GameObject, string, float)

有没有办法做到这一点？

Answer 1

您可以重载您的方法以具有不同的签名，然后调用原始签名。 例如：

void SpawnPylon(GameObject whatSpawn, Transform whereSpawn, float spawnDistance) {
  SpawnPylon(whatSpawn, new Transform[] {whereSpawn}, spawnDistance);
}

Answer 2

如果要更改方法签名中的类型，则必须重载方法：

https://msdn.microsoft.com/en-us/library/ms229029(v=vs.100).aspx

您是否研究过使用不确定数量的参数？

https://msdn.microsoft.com/en-us/library/ms228391(v=vs.90).aspx

为了处理您要的情况，您的类的界面应如下所示：

void SpawnPylon(GameObject whatSpawn, float spawnDistance, params Transform[] whereSpawn);
void SpawnPylon(GameObject whatSpawn, float spawnDistance, string whereSpawn);

然后可以这样称呼它：

SpanPylon(game, distance, where1);

要么

SpanPylon(game, distance, where1, where2);

要么

SpanPylon(game, distance, whereString);

Answer 3

如果要传递参数，请输入所需的参数。使用对象。

void SpawnPylon (GameObject whatSpawn,object whereSpawn,float spawnDistance)
{

    if(whereSpawn is Transform[])
    {
//put your Transform[] specific codes here
    }

if(whereSpawn is Transform)
    {
//put your Transform specific codes here
    }

if(whereSpawn is String)
    {
//put your String specific codes here
    }

}