![](/img/trans.png)
[英]How to split one string column with regular format to multiple columns in Pandas
[英]How to split one column into multiple columns in Pandas using regular expression?
例如,如果我有这样的家庭住址:
71 Pilgrim Avenue, Chevy Chase, MD
在名为“地址”的列中。 我想将其分别分为“街道”,“城市”,“州”列。
使用Pandas实现此目标的最佳方法是什么?
我已经尝试过df[['street', 'city', 'state']] = df['address'].findall(r"myregex")
。
但是我得到的错误是Must have equal len keys and value when setting with an iterable
。
谢谢您的帮助 :)
您可以使用split
通过正则表达式,\\s+
( ,
以及一个或多个空格):
#borrowing sample from `Allen`
df[['street', 'city', 'state']] = df['address'].str.split(',\s+', expand=True)
print (df)
address id street city \
0 71 Pilgrim Avenue, Chevy Chase, MD a 71 Pilgrim Avenue Chevy Chase
1 72 Main St, Chevy Chase, MD b 72 Main St Chevy Chase
state
0 MD
1 MD
而如果需要删除列address
添加drop
:
df[['street', 'city', 'state']] = df['address'].str.split(',\s+', expand=True)
df = df.drop('address', axis=1)
print (df)
id street city state
0 a 71 Pilgrim Avenue Chevy Chase MD
1 b 72 Main St Chevy Chase MD
df = pd.DataFrame({'address': {0: '71 Pilgrim Avenue, Chevy Chase, MD',
1: '72 Main St, Chevy Chase, MD'},
'id': {0: 'a', 1: 'b'}})
#if your address format is consistent, you can simply use a split function.
df2 = df.join(pd.DataFrame(df.address.str.split(',').tolist(),columns=['street', 'city', 'state']))
df2 = df2.applymap(lambda x: x.strip())
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.