Python 2.7.8：不使用格式打印颜色/值

Question

我是python的新手，学习了大约一个月。 我遇到一个问题，当我运行此代码时，应该以红色打印出数字。 第二个示例显示了它真正打印出来的内容，但我感到困惑。 请帮忙。

应该可以打印('Enemy HP:', 1150/1200)
但实际上会打印('Enemy HP:', '\\x1b[91m1150/1200\\x1b[0m\\n')

import random

class bcolors:
    HEADER = '\033[95m'
    OKBLUE = "\x1b[94m"
    OKGREEN = "\x1b[92m"
    WARNING = '\033[93m'
    FAIL = '\x1b[91m'
    ENDC = '\033[0m'
    BOLD = '\033[1m'
    UNDERLINE = '\033[4m'


class Person:
    def __init__(self, hp, mp, atk, df, magic):
        self.maxhp = hp
        self.hp = hp
        self.maxmp = mp
        self.mp = mp
        self.atkl = atk - 10
        self.atkh = atk + 10
        self.df = df
        self.magic = magic
        self.actions = ["Attack", "Magic"]

    def generate_damage(self):
        return random.randrange(self.atkl, self.atkh)

    def generate_spell_damage(self, i):
        mgl = self.magic[i]["dmg"] - 5
        mgh = self.magic[i]["dmg"] + 5
        return random.randrange(mgl, mgh)

    def take_damage(self, dmg):
        self.hp -= dmg
        if self.hp < 0:
            self.hp = 0
        return self.hp

    def get_hp(self):
        return self.hp

    def get_max_hp(self):
        return self.maxhp

    def get_mp(self):
        return self.mp

    def get_max_mp(self):
        return self.maxmp

    def reduce_mp(self, cost):
        self.mp -= cost

    def get_spell_name(self, i):
        return self.magic[i]["name"]

    def get_spell_mp_cost(self, i):
        return self.magic[i]["cost"]

    def choose_action(self):
        i = 1
        print(bcolors.OKBLUE + bcolors.BOLD + "Actions" + bcolors.ENDC)
        for item in self.actions:
            print(str(i) + ":", item)
            i += 1

    def choose_magic(self):
        i = 1
        print(bcolors.OKBLUE + bcolors.BOLD + "Magic" + bcolors.ENDC)
        for spell in self.magic:
            print(str(i) + ":", spell["name"], "(cost:", str(spell["cost"]) + ")")
            i = 1



from classes.game import Person, bcolors


magic = [{"name": "Fire", "cost": 10, "dmg": 100},
         {"name": "Thunder", "cost": 10, "dmg": 124},
         {"name": "Blizzard", "cost": 10, "dmg": 100}]


player = Person(460, 65, 60, 34, magic)
enemy = Person(1200, 65, 45, 25, magic)

running = True
i = 0

print(bcolors.FAIL + bcolors.BOLD + "AN ENEMY ATTACKS!" + bcolors.ENDC)

while running:
    print("======================")
    player.choose_action()
    choice = input("Choose action:")
    index = int(choice) - 1

    if index == 0:
        dmg = player.generate_damage()
        enemy.take_damage(dmg)
        print("You attacked for", dmg, "points of damage.")
    elif index == 1:
        player.choose_magic()
        magic_choice = int(input("Choose magic:")) - 1
        magic_dmg = player.generate_spell_damage(magic_choice)
        spell = player.get_spell_name(magic_choice)
        cost = player.get_spell_mp_cost(magic_choice)

        current_mp = player.get_mp()

        if cost > current_mp:
            print(bcolors.FAIL + "\nNot enough MP\n" + bcolors.ENDC)
            continue

        player.reduce_mp(cost)
        enemy.take_damage(magic_dmg)
        print(bcolors.OKBLUE + "\n" + spell + " deals", str(magic_dmg), "points of damage" + bcolors.ENDC)


    enemy_choice = 1

    enemy_dmg = enemy.generate_damage()
    player.take_damage(enemy_dmg)
    print("Enemy attacks for", enemy_dmg)

    print("----------------------------")
    print("Enemy HP:", bcolors.FAIL + str(enemy.get_hp()) + "/" + str(enemy.get_max_hp()) + bcolors.ENDC + "\n")

    print("Your HP:", bcolors.OKGREEN + str(player.get_hp()) + "/" + str(player.get_max_hp()) + bcolors.ENDC)
    print("Your MP:", bcolors.OKBLUE + str(player.get_mp()) + "/" + str(player.get_max_mp()) + bcolors.ENDC + "\n")



    if enemy.get_hp() == 0:
        print(bcolors.OKGREEN + "You Win!", + bcolors.ENDC)
        running = False
    elif player.get_hp() == 0:
        print(bcolors.FAIL + "Your enemy has defeated you!" + bcolors.ENDC)
        running = False

Answer 1

您的代码在Python 3中可以很好地工作，其中print是一个函数：

>>> print("x", "y")
x y

它的意思是“先打印第一个参数，然后打印分隔符（默认为空格），然后打印第二个参数。

不过在Python 2中：

>>> print("x", "y")
('x', 'y')

打印包含字符串的元组的表示形式。

因此，您可以使用具有许多优点的Python 3，也可以像这样更改代码：

print("Enemy HP:" + bcolors.FAIL + str(enemy.get_hp()) + "/" +  
      str(enemy.get_max_hp()) + bcolors.ENDC + "\n")
# note the + instead of ,

为了打印单个字符串。

Answer 2

对您的其他人打印有用吗？

您在类bcolors的OKGREEN上有一个双引号“”，而不是简单的”，也许它来自这里