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python请求上传文件

[英]python requests upload file

我正在访问一个网站,我想上传一个文件。

我用python编写了代码:

import requests

url = 'http://example.com'
files = {'file': open('1.jpg', 'rb')}
r = requests.post(url, files=files)
print(r.content)

但是似乎没有文件上传,页面与初始页面相同。

我不知道如何上传文件。

该页面的源代码:

<html><head><meta charset="utf-8" /></head>

<body>
<br><br>
Upload<br><br>
<form action="upload.php" method="post"
enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="hidden" name="dir" value="/uploads/" />
<input type="file" name="file" id="file" /> 
<br />
<input type="submit" name="submit" value="Submit" />
</form>

</body>
</html>

几点:

  • 确保将您的请求提交到正确的网址(格式为“ action”)
  • 使用data参数提交其他表单字段('dir','submit')
  • 在文件中包含files (这是可选的)

代码:

import requests

url = 'http://example.com' + '/upload.php'
data = {'dir':'/uploads/', 'submit':'Submit'}
files = {'file':('1.jpg', open('1.jpg', 'rb'))}
r = requests.post(url, data=data, files=files)

print(r.content)

首先,定义上传目录的路径,例如

app.config['UPLOAD_FOLDER'] = 'uploads/'

然后定义允许上传的文件扩展名,

app.config['ALLOWED_EXTENSIONS'] = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])

现在假设您调用函数来处理上传文件,那么您必须编写类似以下的代码,

# Route that will process the file upload
@app.route('/upload', methods=['POST'])
def upload():
    # Get the name of the uploaded file
    file = request.files['file']

    # Check if the file is one of the allowed types/extensions
    if file and allowed_file(file.filename):
        # Make the filename safe, remove unsupported chars
        filename = secure_filename(file.filename)

        # Move the file form the temporal folder to
        # the upload folder we setup
        file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename))

        # Redirect the user to the uploaded_file route, which
        # will basicaly show on the browser the uploaded file
        return redirect(url_for('YOUR REDIRECT FUNCTION NAME',filename=filename))

这样,您可以上传文件并将其存储在您所找到的文件夹中。

我希望这能帮到您。

谢谢。

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