将Obj-c的php的POST变量不起作用

Question

您好，我是iOS和Xcode的新手，但是我必须做一个登录屏幕，尝试连接服务器上的php后，该登录屏幕没有任何响应。

- (IBAction)btnLogin:(id)sender {


    NSInteger success = 0;
    @try {

        if([[self.insUsuario text] isEqualToString:@""] || [[self.insSenha text] isEqualToString:@""] ) {

            [self alertStatus:@"Insira o email e a senha!" :@"Erro" :0];

        } else {
            //ViewPontos *WP = [self.storyboard instantiateViewControllerWithIdentifier:@"ViewPontos"];
            //WP.gUser = self.insUsuario.text;

            NSString *post =[[NSString alloc] initWithFormat:@"usuario=%@&senha=%@",[self.insUsuario text],[self.insSenha text]];

            NSLog(@"PostData: %@",post);

            NSURL *url=[NSURL URLWithString:@"http://emporio56/apiapp/pegarPontos.php"];

            //NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
            NSData *postData = [post dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES];
            NSLog(@"DATA %@", postData);

            NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]];

            NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
            [request setURL:url];
            [request setHTTPMethod:@"POST"];
            [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
            [request setValue:@"application/json" forHTTPHeaderField:@"Accept"];
            //[request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
            [request setValue:@"application/x-www-form-urlencoded charset=utf-8" forHTTPHeaderField:@"Content-Type"];
            [request setHTTPBody:postData];
            [request setHTTPShouldHandleCookies:YES];

            NSLog(@"%@", request);

            NSURLConnection *conn= [[NSURLConnection alloc]initWithRequest:request delegate:self];
            if(conn)
            {

                NSError *error = [[NSError alloc] init];
                NSHTTPURLResponse *response = nil;
                NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error];
                NSLog(@"Response code: %ld", (long)[response statusCode]);

                if ([response statusCode] >= 200 && [response statusCode] < 300)
                {
                    //NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
                   NSLog(@"Response ==> %@", response);

                    NSError *error = nil;
                    NSDictionary *jsonData = [NSJSONSerialization JSONObjectWithData:urlData options:NSJSONReadingMutableContainers error:&error];
                    success = [jsonData[@"success"] integerValue];
                    NSLog(@"Success: %ld",(long)success);

                    if(success == 1)
                    {
                        NSLog(@"Login SUCCESS");
                    } else {

                        NSString *error_msg = (NSString *) jsonData[@"error_message"];
                        [self alertStatus:error_msg :@"Erro" :0];
                    }

                } else {
                    //if (error) NSLog(@"Error: %@", error);
                    [self alertStatus:@"Erro!" :@"Sign in Failed!" :0];
                }


                NSLog(@"Conectado");
            }
            else
            {
                NSLog(@"Nao conectou");
            }
            //[NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[url host]];
        }
    }
    @catch (NSException * e) {
        NSLog(@"Exception: %@", e);
        [self alertStatus:@"Sign in Failed." :@"Erro" :0];
    }
    if (success) {
        [self performSegueWithIdentifier:@"login_success" sender:self];
    }
}

    - (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response {
        // A response has been received, this is where we initialize the instance var you created
        // so that we can append data to it in the didReceiveData method
        // Furthermore, this method is called each time there is a redirect so reinitializing it
        // also serves to clear it
        _responseData = [[NSMutableData alloc] init];
    }

    - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data {
        // Append the new data to the instance variable you declared
        [_responseData appendData:data];
    }

    - (NSCachedURLResponse *)connection:(NSURLConnection *)connection
                      willCacheResponse:(NSCachedURLResponse*)cachedResponse {
        // Return nil to indicate not necessary to store a cached response for this connection
        return nil;
    }

    - (void)connectionDidFinishLoading:(NSURLConnection *)connection {
        // The request is complete and data has been received
        // You can parse the stuff in your instance variable now

    }

    - (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error {
        // The request has failed for some reason!
        // Check the error var
    }

在运行代码以测试并输入用户名和密码之后，我没有从服务器获得响应，始终response = (null) ，有人知道该如何解决？ 因为我已经尝试了大部分可以在网络上找到的代码，但是人们说的却不尽人意，我使用相同的php连接android应用程序，但是它可以正常工作，所以我在我的代码上做错了什么将用户名和密码发布到php文件中，并连接到数据库。

对不起，这个问题，但是我不知道发生了什么

Answer 1

请尝试这个。 希望它能解决您的问题。

NSString *stringUrl = [NSString stringWithFormat:@"http://emporio56/apiapp/pegarPontos.php?usuario=%@&senha=%@",[self.insUsuario text],[self.insSenha text]];
    NSURL *url = [NSURL URLWithString:stringUrl];
    NSURLRequest *request = [NSURLRequest requestWithURL:url];
    [NSURLConnection sendAsynchronousRequest:request
                                       queue:[NSOperationQueue mainQueue]
                           completionHandler:^(NSURLResponse *response,
                                               NSData *data, NSError *connectionError)
     {
         if (data.length > 0 && connectionError == nil)
         {
             NSDictionary *dicYourResponse = [NSJSONSerialization JSONObjectWithData:data options:0 error:NULL];
             NSLog(@"%@",dicYourResponse);
         }
     }];