[英]Regular expression for 6 digit numeric input. Every 6 digits input numbers must be separated by comma
我的UI要求输入User_ID和Supplier_ID,我希望进行字符串验证以接受Supplier_ID的输入,如下所示:
1st scenario: 123456
2nd scenario: 123456,098765
3rd scenario: 123456,098765,345678
虽然它不应该接受以下输入:
1st scenario: Any number less than 6 digits like 123
2nd scenario: Any number more than 6 digits 1234567
3rd scenario: Inputs with comma in the end or even at the beginning - 123456,098765,345678, or ,098765,345678
我将在下面的此查询中使用Supplier_ID的输入:
UPDATE ABC.Items
SET Crit_Limit = 'Y'
WHERE User_ID = 'userID'
AND Supplier_ID in (suppID)
变量suppID将携带来自UI Supplier_ID的输入,因此查询如下所示:
UPDATE ABC.Items
SET Crit_Limit = 'Y'
WHERE User_ID = '007'
AND Supplier_ID in (123456,098765,345678)
无论如何,字段Supplier_ID的长度为6,并且必须为数字。
提前致谢!
这是您正在寻找的表达
^\d{6}(\,\d{6}){0,2}$
将您的正则表达式创建为搜索组,然后首先检查换行符,然后是6位数字,然后检查,
然后是6位数字组。
['123456', '123456,098765', '123456,098765,345678', '123456,0987s65,345678', '12345,098765,345678', '123456/098765' ] .forEach(function(line) { if (line.toString().replace(/(^\\d{6}(,\\d{6})*)/gm, '').length < 1) { console.log(line, "matches"); } else { console.log(line, "does not match"); } });
此模式与您的测试用例以及任何用逗号分隔的6位数字组匹配。
^\d{6}(,\d{6})*$
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