[英]Oracle: How to use Group by and Max(datetime) each record no duplication
我想在每个记录中按Max(Datetime)
分组,但是查询中有重复的记录。 我不要重复的记录。
SQL:
with temp as
(
SELECT a.ref_period, b.status, a.updated_dtm
FROM ir_net_cndn_detail a,ir_net_cndn b
WHERE a.bill_no=b.bill_no
AND b.company_code = a.company_code
AND TO_DATE(a.ref_period,'MM/yyyy') >= TO_DATE(&p_ref_period_start,'MM/yyyy')
AND TO_DATE(a.ref_period,'MM/yyyy') <= TO_DATE(&p_ref_period_end,'MM/yyyy')
)
select a.ref_period, a.status, max(updated_dtm) as updated_dtm
from temp a
where TO_DATE(a.ref_period,'MM/yyyy') >= TO_DATE(&p_ref_period_start,'MM/yyyy')
AND TO_DATE(a.ref_period,'MM/yyyy') <= TO_DATE(&p_ref_period_end,'MM/yyyy')
group by a.ref_period, a.status
恢复SQL:
ref_period | status | update_dtm
01/2015 | I | 01/09/2016 13:29:56
01/2015 | I | 18/05/2017 17:01:52
01/2015 | I | 18/05/2017 16:16:23
07/2015 | I | 01/09/2016 13:29:56
07/2015 | I | 07/01/2016 10:17:39
08/2015 | I | 01/09/2016 13:29:56
09/2015 | N | 05/06/2017 15:59:55
09/2015 | I | 01/09/2016 13:29:56
10/2015 | I | 01/09/2016 13:29:56
但我想要结果:
ref_period | status | update_dtm >> I want max(update)/1 record with no duplication
01/2015 | I | 18/05/2017 17:01:52
07/2015 | I | 01/09/2016 13:29:56
08/2015 | I | 01/09/2016 13:29:56
09/2015 | N | 05/06/2017 15:59:55
10/2015 | I | 01/09/2016 13:29:56
您只ref_period
分组,为什么还要按status
分组? 而是按ref_period
,选择max(update_dtm)
,然后-也要获取status
-使用LAST
函数(如果您不熟悉它,请参阅文档)。 https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions056.htm
...
select ref_period,
min(status) keep (dense_rank last order by update_dtm) as status,
max(update_dtm) as update_dtm
from temp
group by ref_period
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