[英]sql group by sum of all sums
我有一个查询(格式化为Oracle):
select sum(inv.quantity * inv.price), spn.salesperson_name
from invoice inv
inner join salesperson spn on spn.spn_id = inv.spn_id
where inc.invoice_date between to_date('05/01/2017', 'MM/dd/YYYY') and to_date('05/31/2017', 'MM/dd/YYYY')
group by spn.salesperson_name
汇总五月份的发票。 结果类似于:
$446,088.62 Bob
$443,439.29 Sally
$275,097.00 Tom
$95,170.00 George
$53,150.00 Jill
但是,我需要将每个总和除以总和($ 1,312,944.91),这样结果是:
$446,088.62 34% Bob
$443,439.29 34% Sally
$275,097.00 21% Tom
$95,170.00 7% George
$53,150.00 4% Jill
(百分比列的总和应为100%)
有没有一种方法可以在查询中完成此操作?
只需使用解析函数:
select spn.salesperson_name, sum(inv.quantity * inv.price),
sum(inv.quantity * inv.price) / sum(sum(inv.quantity * inv.price)) over () as ratio
from invoice inv inner join
salesperson spn
on spn.spn_id = inv.spn_id
where inc.invoice_date between date '2017-05-01' and date '2017-05-31'
group by spn.salesperson_name;
当功能完全满足您的需要时,最好使用这些功能。 在这种情况下,SQL Standard分析函数RATIO_TO_REPORT
(至少在Oracle和SQL Server中实现)可以完全满足您的需求。 https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions124.htm
具体来说, select
子句可以是:
select sum(inv.quantity * inv.price) AS TOTAL_REVENUE -- use column aliases!
, ratio_to_report(sum(inv.quantity * inv.price)) over () AS RATIO,
, spn.salesperson_name
from ....... (rest of your query goes here)
请注意,此解决方案与“接受的答案”一样,将比率显示为小数而不是百分比(并且不四舍五入)。 如果需要附加百分号,则需要将其转换为字符串...,如果是这样,以下技巧(这是一个技巧!)将为您提供所需的信息:
to_char( ratio_to_report(.....), 'fm99L', 'nls_currency = %' ) AS RATIO, .....
to_char
的L
元素用于货币符号; 您将货币符号定义为百分号。
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