python django字典

Question

我有这种格式的清单：

[{'BURGLARY': [0, 1, 1, 0], 'PHYSICAL ASSAULT': [0, 0, 1, 0], 'ROBBERY': 
  [0, 0, 0, 1], 'VANDALISM': [2, 0, 1, 0], 'THEFT': [1, 3, 2, 1], 'DRUGS AND SUBSTANCE ABUSE': [0, 0, 1, 0], 'SEXUAL HARASSMENT': [0, 0, 0, 1]}]

我想将其格式更改为：

[
  {
   name:"BURGLARY",
   data:[0, 1, 1, 0]
  }
   {
   name:"PHYSICAL ASSAULT",
   data:[0, 0, 1, 0]
  }
...
]

我该如何存档？ 请帮忙。

Answer 1

data = [{'BURGLARY': [0, 1, 1, 0], 'PHYSICAL ASSAULT': [0, 0, 1, 0], 'ROBBERY': 
      [0, 0, 0, 1], 'VANDALISM': [2, 0, 1, 0], 'THEFT': [1, 3, 2, 1], 'DRUGS 
      AND SUBSTANCE ABUSE': [0, 0, 1, 0], 'SEXUAL HARASSMENT': [0, 0, 0, 1]}]
rlt = [{'name': key, 'data': val} for key,val in data[0].items()]

rlt是你想要的

Answer 2

data = [{'BURGLARY': [0, 1, 1, 0], 'PHYSICAL ASSAULT': [0, 0, 1, 0], 'ROBBERY': 
  [0, 0, 0, 1], 'VANDALISM': [2, 0, 1, 0], 'THEFT': [1, 3, 2, 1], 'DRUGS AND SUBSTANCE ABUSE': [0, 0, 1, 0], 'SEXUAL HARASSMENT': [0, 0, 0, 1]}]

new_data = [{ "name": k, "data" : data[0][k]} for k in data[0]]

输出：

[{'data': [0, 0, 0, 1], 'name': 'ROBBERY'},
 {'data': [2, 0, 1, 0], 'name': 'VANDALISM'},
 {'data': [0, 0, 0, 1], 'name': 'SEXUAL HARASSMENT'},
 {'data': [1, 3, 2, 1], 'name': 'THEFT'},
 {'data': [0, 1, 1, 0], 'name': 'BURGLARY'},
 {'data': [0, 0, 1, 0], 'name': 'PHYSICAL ASSAULT'},
 {'data': [0, 0, 1, 0], 'name': 'DRUGS AND SUBSTANCE ABUSE'}]

Answer 3

a=[{'BURGLARY': [0, 1, 1, 0], 'PHYSICAL ASSAULT': [0, 0, 1, 0], 'ROBBERY': [0, 0, 0, 1], 'VANDALISM': [2, 0, 1, 0], 'THEFT': [1, 3, 2, 1], 'DRUGS AND SUBSTANCE ABUSE': [0, 0, 1, 0], 'SEXUAL HARASSMENT': [0, 0, 0, 1]}]
result=[]
for b in a:
    for i,j in b.items():
        result.append({"name":i,"data":j})
print(result)

输出

[{'name': 'VANDALISM', 'data': [2, 0, 1, 0]}, {'name': 'SEXUAL HARASSMENT', 'data': [0, 0, 0, 1]}, {'name': 'PHYSICAL ASSAULT', 'data': [0, 0, 1, 0]}, {'name': 'DRUGS AND SUBSTANCE ABUSE', 'data': [0, 0, 1, 0]}, {'name': 'THEFT', 'data': [1, 3, 2, 1]}, {'name': 'ROBBERY', 'data': [0, 0, 0, 1]}, {'name': 'BURGLARY', 'data': [0, 1, 1, 0]}]