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[英]count the total numbers of unique letters occurred once in a string in python?
[英]Python: Unique numbers in string
我想在第二列中保留唯一的整数,并在上一列中打印该条目。 但是我无法将字符串转换为整数并得到错误: TypeError:'int'对象不可迭代
输入文件
A 1 108.80
A 1 8.33
B 2 45.10
B 2 3.96
B 2 3.94
A 3 1.96
A 3 2.94
输出量
A
B
A
脚本
with open('test.pdb') as infile:
for line in infile:
data = int(line.split()[1])
seen = set()
for number in range(data):
unique = [x for x in number if x not in seen]
seen.update(unique)
print(unique)
这是您(可能)想要的:
seen = set()
with open('test.pdb') as infile:
for line in infile:
unique, data = line.split()[0:2]
if data not in seen:
print(unique)
seen.add(data)
给定该示例,下面是处理该列表的列表:
with open(fn) as f:
seen=set()
print '\n'.join([c1 for c1,c2 in (line.split()[0:2] for line in f)
if not (c2 in seen or seen.add(c2))])
印刷品:
A
B
A
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