在Swift 3中将字符串数组与字典进行比较

Question

我有字符串数组， let filterClassName = ["A","B"]

现在我有了字典，看起来像：

var responseArray: [[String: Any]] = []

responseArray.append(["id": 1,"name": "Prateek", "className": "A"])
responseArray.append(["id": 1,"name": "rateek", "className": "B"])
responseArray.append(["id": 3,"name": "ateek", "className": "C"])
responseArray.append(["id": 4,"name": "teek", "className": "D"])
responseArray.append(["id": 5,"name": "eek", "className": "A"])
responseArray.append(["id": 6,"name": "ek", "className": "E"])

现在从responseArray这是我的字典，我想要所有与filterClassName提到的className匹配的值

因此，我应该以数组形式输出：

[“ id”：1，“ name”：“ Prateek”，“ className”：“ A”]，[“ id”：1，“ name”：“ rateek”，“ className”：“ B”]，[“ id“：5，”名称“：” eek“，” className“：” A“]

提前致谢！

这是我尝试过的：

for value in filterClassName {
    let cal = responseArray.filter { (($0["className"] as! String).contains(value)) }
    for value in cal {
        let valuesss = value
        print ("valuesss" + String(describing: valuesss))
    }
}

我上面的答案很基本，但是我希望这样的工作：

let cal = responseArray.filter { (($0["className"] as! String).contains(filterClassName)) }

简而言之，单行过滤，没有for循环，因为我讨厌它们！

Answer 1

您已经很接近了，但是反过来：

let filteredItems = responseArray.filter{ filterClassName.contains($0["className"] as! String) } 

---

但是，正如Hamish在评论中提到的那样，使用自定义结构更有效。

您的代码：

let filterClassName = ["A","B"]

var responseArray: [[String: Any]] = []

responseArray.append(["id": 1,"name": "Prateek", "className": "A"])
responseArray.append(["id": 1,"name": "rateek", "className": "B"])
responseArray.append(["id": 3,"name": "ateek", "className": "C"])
responseArray.append(["id": 4,"name": "teek", "className": "D"])
responseArray.append(["id": 5,"name": "eek", "className": "A"])
responseArray.append(["id": 6,"name": "ek", "className": "E"])

要添加的代码：

struct Student {
    let name, className : String
    let id : Int

    init?(dictionary: [String:Any]) {
        guard let id = dictionary["id"] as? Int,
            let name = dictionary["name"] as? String,
            let className = dictionary["className"] as? String else { return nil }
        self.id = id
        self.name = name
        self.className = className
    }
}

let students = responseArray.flatMap { Student(dictionary:$0) }
let filteredItems = students.filter{ filterClassName.contains($0.className) }
print(filteredItems)

Answer 2

您必须检查filterClassName数组是否包含类名称。

let filteredResponse = responseArray.filter { filterClassName.contains($0["className"] as! String) }