[英]Python socket.error
我在aaronbell.com上找到了该脚本,试图通过它使用Dashbutton连接到IFTTT。 我的Pi抛出此错误:
Traceback (most recent call last):
File "dash.py", line 30, in <module>
rawSocket = socket.socket(socket.AF_PACKET, socket.SOCK_RAW, socket.htons(0x0003))
File "/usr/lib/python2.7/socket.py", line 187, in __init__
_sock = _realsocket(family, type, proto)
socket.error: [Errno 1] Operation not permitted
这是我的脚本:
import socket
import struct
import binascii
import time
import json
import urllib2
ifttt_key = 'loremipsum'
ifttt_url_button = 'https://maker.ifttt.com/trigger/button_was_pressed/with/key/' + ifttt_key
macs = {
'AC63BEBA94E1' : 'MiXT4Pi'
}
def trigger_url(url):
data = '{ "value1" : "' + time.strftime("%Y-%m-%d") + '", "value2" : "' + time.strftime("%H:%M") + '" }'
req = urllib2.Request(url, data, {'Content-Type': 'application/json'})
f = urllib2.urlopen(req)
response = f.read()
f.close()
return response
def button_was_pressed():
print 'triggering button event, response: ' + trigger_url(ifttt_url_button)
rawSocket = socket.socket(socket.AF_PACKET, socket.SOCK_RAW, socket.htons(0x0003))
while True:
packet = rawSocket.recvfrom(2048)
ethernet_header = packet[0][0:14]
ethernet_detailed = struct.unpack("!6s6s2s", ethernet_header)
# skip non-ARP packets
ethertype = ethernet_detailed[2]
if ethertype != '\x08\x06':
continue
# read out data
arp_header = packet[0][14:42]
arp_detailed = struct.unpack("2s2s1s1s2s6s4s6s4s", arp_header)
source_mac = binascii.hexlify(arp_detailed[5])
source_ip = socket.inet_ntoa(arp_detailed[6])
dest_ip = socket.inet_ntoa(arp_detailed[8])
if source_mac in macs:
#print "ARP from " + macs[source_mac] + " with IP " + source_ip
if macs[source_mac] == 'MiXT4Pi':
button_was_pressed()
else:
print "Unknown MAC " + source_mac + " from IP " + source_ip
我尝试将第30行更改为:
rawSocket = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.htons(0x0003))
但发生类似的错误:
Traceback (most recent call last):
File "dash.py", line 30, in <module>
rawSocket = socket.socket(socket.AF_INET, socket.SOCK_RAW, socket.htons(0x0003))
File "/usr/lib/python2.7/socket.py", line 187, in __init__
_sock = _realsocket(family, type, proto)
socket.error: [Errno 22] Invalid argument
在此先感谢您的帮助!
换线
rawSocket = socket.socket(socket.AF_PACKET, socket.SOCK_RAW, socket.htons(0x0003))
对此
rawSocket = socket.socket(socket.AF_PACKET, socket.SOCK_RAW, 0)
这将起作用。
首先,将域设置为“ AF_INET”,就像在struct sockaddr_in中一样(如上)。接下来,类型参数告诉内核这是哪种套接字:SOCK_STREAM或SOCK_DGRAM。 最后,只需将协议设置为“ 0”,即可让socket()根据类型选择正确的协议。 (注意:域的数量比我列出的要多。类型的数量比我列出的要多。请参见socket()手册页。此外,还有一种“更好”的方式来获取协议。 请参见getprotobyname( )手册页 。)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.