psql运行sql文件结果

Question

当我运行命令时：

psql -h localhost -p 5432 -U meee -d my_db -f sqltest.sql

它显示：

CREATE VIEW
ALTER TABLE

但是我希望它像pgadmin一样显示给我（例如：查询已在45毫秒内成功执行，但未返回任何结果）

Answer 1

在sqltest.sql的开头添加命令\\ timing，然后您会看到每个命令的时间

例如script.sql： \\timing select 2 ; select 1; create table tablax(i int); \\timing select 2 ; select 1; create table tablax(i int);

或者，如果您希望从脚本的开始一直到结束都需要，请在开始时向scritp添加一些命令： create temp table tab (time1 time,time2 time); insert into tab (time1) select now()::time; create temp table tab (time1 time,time2 time); insert into tab (time1) select now()::time;

最后： update tab set time2=now()::time; select time2-time1 as time_Elapsed from tab; update tab set time2=now()::time; select time2-time1 as time_Elapsed from tab;

例如：

create temp table tab (time1 time,time2 time);

insert into tab (time1) select now()::time;

...您的脚本代码

... update tab set time2=now()::time; select time2-time1 as time_Elapsed from tab; update tab set time2=now()::time; select time2-time1 as time_Elapsed from tab;

Answer 2

使用a psql的命令参数：

psql -h localhost -p 5432 -U meee -d my_db -af sqltest.sql

https://www.postgresql.org/docs/current/static/app-psql.html

并将\\timing on脚本的顶部