[英]Connecting to Azure Table Storage in R
我一直在尝试连接到 R 中的 Azure 表存储。谷歌搜索没有返回任何关于使用 R 连接到 Rest API 进行表存储的人。 文档在这里。 我已经尝试将现有的关于 blob 存储的问题进行连接(我什至无法使用它连接到 blob)并重新使用它进行表存储查询。 以下:
library(httr)
url <- "https://rpoc.table.core.windows.net:443/dummytable(PartitionKey='0dfe725b-bd43-4d9d-b58a-90654d1d8741',RowKey='00b7595d-97c3-4f29-93de-c1146bcd3d33')?$select=<comma-separated-property-names>"
sak<-"u4RzASEJ3qbxSpf5VL1nY08MwRz4VKJXsyYKV2wSFlhf/1ZYV6eGkKD3UALSblXsloCs8k4lvCS6sDE9wfVIDg=="
requestdate<- http_date(Sys.time())
signaturestring<-paste0("GET",paste(rep("\n",12),collapse=""),
"x-ms-date:",requestdate,"
x-ms-version:2015-12-11")
headerstuff<-add_headers(Authorization=paste0("SharedKey rpoc:",
RCurl::base64(digest::hmac(key=RCurl::base64Decode(sak, mode="raw"),
object=enc2utf8(signaturestring),
algo= "sha256", raw=TRUE))),
`x-ms-date`=requestdate,
`x-ms-version`= "2015-12-11",
`DataServiceVersion` = "3.0;NetFx",
`MaxDataServiceVersion` = "3.0;NetFx" )
content(GET(url,config = headerstuff, verbose() ))
控制台 output:
-> GET /dummytable(PartitionKey='0dfe725b-bd43-4d9d-b58a-90654d1d8741',RowKey='00b7595d-97c3-4f29-93de-c1146bcd3d33')?$select=<comma-separated-property-names> HTTP/1.1
-> Host: rpoc.table.core.windows.net
-> User-Agent: libcurl/7.53.1 r-curl/2.6 httr/1.2.1
-> Accept-Encoding: gzip, deflate
-> Accept: application/json, text/xml, application/xml, */*
-> Authorization: SharedKey rpoc:nQWNoPc1l/kXydUw4rNq8MBIf/arJXkI3jZv+NttqMs=
-> x-ms-date: Mon, 24 Jul 2017 18:49:52 GMT
-> x-ms-version: 2015-12-11
-> DataServiceVersion: 3.0;NetFx
-> MaxDataServiceVersion: 3.0;NetFx
->
<- HTTP/1.1 403 Server failed to authenticate the request. Make sure the value of Authorization header is formed correctly including the signature.
<- Content-Length: 299
<- Content-Type: application/json
<- Server: Microsoft-HTTPAPI/2.0
<- x-ms-request-id: 2c74433e-0002-00b3-5aad-04d4db000000
<- Date: Mon, 24 Jul 2017 18:49:53 GMT
<-
$odata.error
$odata.error$code
[1] "AuthenticationFailed"
$odata.error$message
$odata.error$message$lang
[1] "en-US"
$odata.error$message$value
[1] "Server failed to authenticate the request. Make sure the value of Authorization header is formed correctly including the signature.\nRequestId:2c74433e-0002-00b3-5aad-04d4db000000\nTime:2017-07-24T18:49:54.3878127Z"
问题看起来是身份验证标头。 任何有关如何解决此问题的帮助将不胜感激。 我真的很惊讶更多的人不将 ATS 与 R 一起使用,因为它用途广泛。
根据Azure存储身份验证的REST参考,根据您的错误信息和代码,问题AuthenticationFailed
应该由Table Service的错误签名字符串引起,而不包含12个重复符号\\n
,这与Blob,Queue的不同和文件服务。 请仔细查看Authentication for the Azure Storage Services
的参考Authentication for the Azure Storage Services
以了解表服务的差异格式,如下所示。
表服务(共享密钥验证)
StringToSign = VERB + "\\n" + Content-MD5 + "\\n" + Content-Type + "\\n" + Date + "\\n" + CanonicalizedResource;
表服务(共享密钥Lite身份验证)
StringToSign = Date + "\\n" CanonicalizedResource
希望能帮助到你。
我的解决方案基于PUT blob问题( Azure PUT Blob身份验证在R中失败 ),然后我适应使用GET而不是PUT和表而不是blob。
library(httr)
account <- "account"
container <- "container"
key <- "u4RzASEJ..9wfVIDg=="
url <- paste0("https://", account, ".table.core.windows.net/", container)
requestdate <- format(Sys.time(),"%a, %d %b %Y %H:%M:%S %Z", tz="GMT")
content_length <- 0
signature_string <- paste0("GET", "\n", # HTTP Verb
"\n", # Content-MD5
"text/plain", "\n", # Content-Type
requestdate, "\n", # Date
# Here comes the Canonicalized Resource
"/",account, "/",container)
headerstuff <- add_headers(Authorization=paste0("SharedKey ",account,":",
RCurl::base64(digest::hmac(key =
RCurl::base64Decode(key, mode = "raw"),
object = enc2utf8(signature_string),
algo = "sha256", raw = TRUE))),
`x-ms-date`= requestdate,
`x-ms-version`= "2015-02-21",
`Content-Type`="text/plain")
xml_body = content(GET(url, config = headerstuff, verbose()))
派对有点晚了,但是:现在有一个AzureTableStor package,它也在CRAN上。
library(AzureTableStor)
# storage account endpoint
endp <- table_endpoint("https://mystorageacct.table.core.windows.net", key="mykey")
# Cosmos DB w/table API endpoint
endp <- table_endpoint("https://mycosmosdb.table.cosmos.azure.com:443", key="mykey")
list_storage_tables(endp)
tab <- storage_table(endp, "mytable")
insert_table_entity(tab, list(
RowKey="row1",
PartitionKey="partition1",
firstname="Bill",
lastname="Gates"
))
get_table_entity(tab, "row1", "partition1")
免责声明:我是这个 package 的开发者。
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