Python超时似乎不起作用

Question

我有以下代码；

def ip_addresses():
    # Get external ipv4
    try:
        response = urllib2.urlopen('http://icanhazip.com', timeout = 2)
        out = response.read()
        public_ipv4 = re.sub('\n', '', out)
    except:
        public_ipv4 = "failed to retrieve public_ipv4"

在正常情况下，当收到来自http://icanhazip.com的响应时，输出是这样的；

xxx@xxx:/var/log$ date && tail -1 xxx.log
Tue Jul 25 **07:43**:18 UTC 2017  {"public_ipv4": "208.185.193.131"}, "date": "2017-07-25 **07:43**:01.558242"

因此，当前日期和日志生成日期相同。 但是，如果有例外，就会发生这种情况。

xxx@xxx:/var/log$ date && tail -1 xxx.log
Tue Jul 25 **07:30**:25 UTC 2017  {"public_ipv4": "failed to retrieve public_ipv4"},"date": "2017-07-25 **07:23**:01.525444"

为什么“超时”不起作用？

Answer 1

尝试以这种方式获取详细的异常详细信息，然后调查错误的根本原因，时间差。使用此格式...

import sys
try:
    1 / 0
except:
    print sys.exc_info()