Powershell使用参数调用基于哪个参数被调用的函数

Question

我只是跳入PowerShell，并试图编写一个脚本，该脚本执行我根据调用的参数创建的功能。

示例：send-notification -WhichNotifcation dosomething

示例2：send-notification -WhichNotification dosomethingelse

我现在所拥有的只是第一个函数，而没有第二个。 我究竟做错了什么？

param(
    [parameter(Mandatory = $true)]
    [ValidateSet("dosomething", "dosomethingelse")]
    [ValidateNotNull()]
    [string]$WhichNotification
)

#Variables
$mailTo = "user@something.com"
$mailFrom = "user@somethingelse.com"
$smtpServer = "x.x.x.x"
$mailSubject1 = "Do Something"
$MailSubject2 = "do something else"

function Send-dosomething
{

    Send-MailMessage -To $mailTo -From $mailFrom -SmtpServer $smtpServer -Subject $mailSubject1 -Body "message1"
}


function Send-dosomethingelse
{
    Send-MailMessage -To $mailTo -From $mailFrom -SmtpServer $smtpServer -Subject $MailSubject2 -Body "message2"
}


if ($WhichNotification = "dosomething") {

    Send-dosomething

}
elseif ($WhichNotification = "dosomethingelse") {

    Send-dosomethingelse

}
else {

    Write-Host "Invalid"

}

Answer 1

我也倾向于做的常见错误，您正在做的是：

if ($WhichNotification = "dosomething") 

这样做是将变量$WhichNotification设置为“ $WhichNotification ”-在if块中的结果为$true 。

您要做的是：

if ($WhichNotification -eq "dosomething")