同一页上的多个倒计时JS

Question

我对JS一无所知，所以请给我一些时间。 我正在使用W3schools网站的倒计时。 问题是，即使我给两个倒计时分别提供了ID，但它们似乎在运行相同的倒计时，而不是分开。 两者似乎都运行sec-cd。

如何允许这两个倒数计时分别工作？

HTML

<div id="main">
  <h1><u><b>Countdown 1</b></u></h1>
  <h1 id="main-cd"></h1>
  <div class="secondary">
    <h1><u><b>Countdown 2</b></u></h1>
    <h1 id="sec-cd"></h1>
  </div>

</div>

JavaScript的

var countDownDate = new Date("August 29, 2017 19:00:00 GMT").getTime();
var x = setInterval(function() {

  var now = new Date().getTime();

  var distance = countDownDate - now;

  var days = Math.floor(distance / (1000 * 60 * 60 * 24));
  var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
  var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
  var seconds = Math.floor((distance % (1000 * 60)) / 1000);

  document.getElementById("main-cd").innerHTML = days + "d " + hours + "h " + minutes + "m " + seconds + "s ";

  if (distance < 0) {
    clearInterval(x);
    var ongoing = document.getElementById("main-cd").innerHTML = "Fin";
  }

}, 1000);

var countDownDate = new Date("August 28, 2017 19:00:00 GMT").getTime();

var x = setInterval(function() {

  var now = new Date().getTime();

  var distance = countDownDate - now;

  var days = Math.floor(distance / (1000 * 60 * 60 * 24));
  var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
  var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
  var seconds = Math.floor((distance % (1000 * 60)) / 1000);

  document.getElementById("sec-cd").innerHTML = days + "d " + hours + "h " + minutes + "m " + seconds + "s ";

  if (distance < 0) {
    clearInterval(x);
    var ongoing = document.getElementById("sec-cd").innerHTML = "Fin";
  }

}, 1000);

JSFiddle链接： https ：//jsfiddle.net/az0upkxu/

Answer 1

这是因为您要覆盖相同的变量。 请使用另一个变量。

var countDownDate = new Date("August 29, 2017 19:00:00 GMT").getTime();

var countDownDate_2 = new Date("August 28, 2017 19:00:00 GMT").getTime();// renmaed variable

还可以使用这些参数在代码内使用这些不同的变量名称。

下面的代码将起作用。

var countDownDate = new Date("August 29, 2017 19:00:00 GMT").getTime();
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();

    // Find the distance between now an the count down date
    var distance = countDownDate - now;

    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);

    // Output the result in an element with id="demo"
    document.getElementById("main-cd").innerHTML = days + "d " + hours + "h "
    + minutes + "m " + seconds + "s ";

    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        var ongoing =document.getElementById("main-cd").innerHTML = "Event Ongoing";
    }

}, 1000);
// Set the date we're counting down to
var countDownDate_2 = new Date("August 28, 2017 19:00:00 GMT").getTime();

// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();

    // Find the distance between now an the count down date
    var distance = countDownDate_2 - now;

    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);

    // Output the result in an element with id="demo"
    document.getElementById("sec-cd").innerHTML = days + "d " + hours + "h "
    + minutes + "m " + seconds + "s ";

    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        var ongoing =document.getElementById("sec-cd").innerHTML = "Season has eneded!";
    }

}, 1000);

Answer 2

您正在使用countDownDate变量两次。 只需重新声明它具有countDownDateTwo并将distance更改为等于countDownDateTwo - now就可以了。

注意变量名，这就是范围是关键的原因。