同一頁上的多個倒計時JS

Question

我對JS一無所知，所以請給我一些時間。 我正在使用W3schools網站的倒計時。 問題是，即使我給兩個倒計時分別提供了ID，但它們似乎在運行相同的倒計時，而不是分開。 兩者似乎都運行sec-cd。

如何允許這兩個倒數計時分別工作？

HTML

<div id="main">
  <h1><u><b>Countdown 1</b></u></h1>
  <h1 id="main-cd"></h1>
  <div class="secondary">
    <h1><u><b>Countdown 2</b></u></h1>
    <h1 id="sec-cd"></h1>
  </div>

</div>

JavaScript的

var countDownDate = new Date("August 29, 2017 19:00:00 GMT").getTime();
var x = setInterval(function() {

  var now = new Date().getTime();

  var distance = countDownDate - now;

  var days = Math.floor(distance / (1000 * 60 * 60 * 24));
  var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
  var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
  var seconds = Math.floor((distance % (1000 * 60)) / 1000);

  document.getElementById("main-cd").innerHTML = days + "d " + hours + "h " + minutes + "m " + seconds + "s ";

  if (distance < 0) {
    clearInterval(x);
    var ongoing = document.getElementById("main-cd").innerHTML = "Fin";
  }

}, 1000);

var countDownDate = new Date("August 28, 2017 19:00:00 GMT").getTime();

var x = setInterval(function() {

  var now = new Date().getTime();

  var distance = countDownDate - now;

  var days = Math.floor(distance / (1000 * 60 * 60 * 24));
  var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
  var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
  var seconds = Math.floor((distance % (1000 * 60)) / 1000);

  document.getElementById("sec-cd").innerHTML = days + "d " + hours + "h " + minutes + "m " + seconds + "s ";

  if (distance < 0) {
    clearInterval(x);
    var ongoing = document.getElementById("sec-cd").innerHTML = "Fin";
  }

}, 1000);

JSFiddle鏈接： https ：//jsfiddle.net/az0upkxu/

Answer 1

這是因為您要覆蓋相同的變量。 請使用另一個變量。

var countDownDate = new Date("August 29, 2017 19:00:00 GMT").getTime();

var countDownDate_2 = new Date("August 28, 2017 19:00:00 GMT").getTime();// renmaed variable

還可以使用這些參數在代碼內使用這些不同的變量名稱。

下面的代碼將起作用。

var countDownDate = new Date("August 29, 2017 19:00:00 GMT").getTime();
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();

    // Find the distance between now an the count down date
    var distance = countDownDate - now;

    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);

    // Output the result in an element with id="demo"
    document.getElementById("main-cd").innerHTML = days + "d " + hours + "h "
    + minutes + "m " + seconds + "s ";

    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        var ongoing =document.getElementById("main-cd").innerHTML = "Event Ongoing";
    }

}, 1000);
// Set the date we're counting down to
var countDownDate_2 = new Date("August 28, 2017 19:00:00 GMT").getTime();

// Update the count down every 1 second
var x = setInterval(function() {

    // Get todays date and time
    var now = new Date().getTime();

    // Find the distance between now an the count down date
    var distance = countDownDate_2 - now;

    // Time calculations for days, hours, minutes and seconds
    var days = Math.floor(distance / (1000 * 60 * 60 * 24));
    var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60));
    var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60));
    var seconds = Math.floor((distance % (1000 * 60)) / 1000);

    // Output the result in an element with id="demo"
    document.getElementById("sec-cd").innerHTML = days + "d " + hours + "h "
    + minutes + "m " + seconds + "s ";

    // If the count down is over, write some text 
    if (distance < 0) {
        clearInterval(x);
        var ongoing =document.getElementById("sec-cd").innerHTML = "Season has eneded!";
    }

}, 1000);

Answer 2

您正在使用countDownDate變量兩次。 只需重新聲明它具有countDownDateTwo並將distance更改為等於countDownDateTwo - now就可以了。

注意變量名，這就是范圍是關鍵的原因。