如何将逗号分隔的字典字符串拆分为Pandas数据框

Question

我有以下格式的字符串：

{apple:"34253453",oranges:"Sweet",x:"COOL"},{apple:"34222453",oranges:"Dry",x:"WARM"},{apple:"31113453",oranges:"Bitter",x:"HOT"},{apple:"38883453",oranges:"Sweet",x:"COOL"}

并希望创建一个数据框，其列标签为“ apple”，“ oranges”，“ x”，并将值放置在它们各自的行中。

我尝试使用此解决方案： Python将逗号分隔的列表转换为熊猫数据框，以及将ast.literal_eval转换为列表，然后再将其转换为数据框，但没有运气。

Answer 1

您的字符串是无效的json ，因此有必要先进行替换：

import ast

s = '{apple:"34253453",oranges:"Sweet",x:"COOL"},{apple:"34222453",oranges:"Dry",x:"WARM"},{apple:"31113453",oranges:"Bitter",x:"HOT"},{apple:"38883453",oranges:"Sweet",x:"COOL"}'

ss = '[' + s.replace('{', '{"').replace(':"','":"').replace('",', '","') + ']'
print (ss)

[{"apple":"34253453","oranges":"Sweet","x":"COOL"},
 {"apple":"34222453","oranges":"Dry","x":"WARM"},
 {"apple":"31113453","oranges":"Bitter","x":"HOT"},
 {"apple":"38883453","oranges":"Sweet","x":"COOL"}]

---

df = pd.DataFrame(ast.literal_eval(ss))
print (df)
      apple oranges     x
0  34253453   Sweet  COOL
1  34222453     Dry  WARM
2  31113453  Bitter   HOT
3  38883453   Sweet  COOL

---

df = pd.DataFrame(pd.io.json.loads(ss))
print (df)
      apple oranges     x
0  34253453   Sweet  COOL
1  34222453     Dry  WARM
2  31113453  Bitter   HOT
3  38883453   Sweet  COOL