[英]SQL Server - Assign default DateTime value to parameters in Stored Procedure
[英]Setting default parameters for a SQL Server stored procedure
我正在尝试将@Day
的默认值设置为当前日期。 但是,我在初始DATEADD(Day, DATEDIFF(Day, 0, GETDATE()), 0)
以及它下面的所有@Day
上遇到了一些错误。 我以为在@Day DateTime
程序下的@Day DateTime
声明为@Day
但出现错误:
必须声明标量变量“ @Day”
有人知道该怎么办吗?
ALTER PROCEDURE [dbo].[InsertWeeklyRuns]
@Day DateTime = DATEADD(Day, DATEDIFF(Day, 0, GETDATE()), 0)
AS
BEGIN
SET NOCOUNT ON
DECLARE @Enddate DATETIME
DECLARE @StartDate DATETIME
DECLARE @F1Runs INT
DECLARE @F2Runs INT
DECLARE @F3Runs INT
DECLARE @F1Alarms INT
DECLARE @F2Alarms INT
DECLARE @F3Alarms INT
SET @Day = DATEADD(dd, DATEDIFF(dd, 0, @Day), 0)
SET @Enddate = CASE
WHEN @Day > DATEADD(Day, DATEDIFF(Day, 0, GETDATE()), 0)
THEN DATEADD(Day, DATEDIFF(Day, 0, GETDATE()), 0)
ELSE DATEADD(Day, 1, @Day)
END
SET @StartDate = @Enddate - 7
谢谢
这应该可以按预期工作:
CREATE PROCEDURE [dbo].[InsertWeeklyRuns]
@Day DateTime
AS
BEGIN
SET NOCOUNT ON
Declare @Enddate Datetime
Declare @StartDate Datetime
Declare @F1Runs Int
Declare @F2Runs Int
Declare @F3Runs Int
Declare @F1Alarms Int
Declare @F2Alarms Int
Declare @F3Alarms Int
DECLARE @today date = CAST(GETDATE() AS date);
IF @Day IS NULL
Set @Day = @today
Set @Enddate = CASE WHEN @Day >= @today THEN @today ELSE DATEADD(Day, 1, @Day) END
Set @StartDate = @Enddate - 7
END
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