如何只按字母顺序打印嵌套在列表中，字典中的内部词典的键？

Question

理想情况下，打印结果将是：

- ainner  
- binner1  
- cinner2  
- dinner3

但是我只设法使用.keys()打印出键。

json_dict = {"key": "value", "key1": [{"binner": "inner_value"}, {"ainner1": "inner_value1"}, {"cinner": "inner_value"}, {"dinner1": "inner_value1"}]}

def pprint(a_dict):
    for k in a_dict["key1"]:
        print("-", k.keys())

pprint(json_dict)  

结果是：

- dict_keys(['binner'])
- dict_keys(['ainner1'])    
- dict_keys(['dinner1'])
- dict_keys(['cinner'])

我正在寻找类似的功能： {print("- {}".format(k)) for k in sorted(a_dict)}适用于非嵌套词典

Answer 1

您要返回的是密钥的名称。

json_dict = {"key": "value", "key1": [{"binner": "inner_value"},{"ainner1": "inner_value1"}]}

for i in json_dict['key1']:
    for x in i.keys():
        print (x)

结果是这样

binner
ainner1

您将需要遍历.keys（）来访问密钥名称。

Answer 2

您可以尝试以下方法：

json_dict = {"key": "value", "key1": [{"binner": "inner_value"}, {"ainner1": "inner_value1"}, {"cinner": "inner_value"}, {"dinner1": "inner_value1"}]}
new_data = sorted([list(i.keys())[0] for i in json_dict["key1"]])

输出：

['ainner1', 'binner', 'cinner', 'dinner1']

Answer 3

一旦有了所需的对象（ key1的值）

a = [{"binner": "inner_value"}, {"ainner1": "inner_value1"},
     {"cinner": "inner_value"}, {"dinner1": "inner_value1"}]

import itertools

从每个字典中获取键

b = map(dict.keys, a)

展平关键视图对象列表

c = itertools.chain.from_iterable(b)

分类

d = sorted(c)

打印

fmt_s = '- {}'
for thing in d:
    print(fmt_s.format(thing))

Answer 4

您发布的代码完成了大部分工作，更改了以下的pprint ：

def pprint(a_dict):
    for k in a_dict["key1"]:
       print("-", k.keys())

至

def pprint(a_dict):
    for k in a_dict["key1"]:
        print("-", list(k.keys())[0])

收益率：

- binner
- ainner1
- cinner
- dinner1