[英]jq: selecting subset of keys from nested object
输入:
{"success": true, "results": {"a": …, "b": …, "c": …}}
给定我想要保留b
期望输出:
{"success": true, "results": {"b": …}}
我尝试过的事情:
$ jq 'del(select(.results.b | not))'
{"success": true, "results": {"a": …, "b": …, "c": …}}
# removes nothing from "results"
$ jq 'with_entries(select(.key == "success" or .key == "results.b"))'
{"success": true}
# nested comparison not understood; returns only "success"
谢谢!
这是一种解决方案:
.results |= {b}
样品运行
$ jq -M '.results |= {b}' <<< '{"success":true, "results":{"a": "…", "b": "…", "c": "…"}}'
{
"success": true,
"results": {
"b": "…"
}
}
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