[英]Use jQuery and ajax to send serialized form as value in data object to php
消除这个问题,我想通过数据对象中的AJAX将序列化的表单字符串发送给PHP。 我的表格是:
<form id="add_project_form" method="post">
<div class="form_group">
<p>Title:</p>
<input type="text" name="title">
</div>
<div class="form_group form_select" id="visible">
<p>Visible:
<select name="visible">
<option>1</option>
<option>0</option>
</select>
</p>
</div>
<a href="javascript:void(0)" id="submit_project">Add Project</a>
</form>
我可以像数据那样做:$('form')。serialize(),但似乎无法在对象中传递它。
$('#submit_project').click(function() {
$.ajax({
url: 'ajax_calls.php',
type: 'POST',
data: {
add_project_call: true,
form_data: $('#add_project_form').serialize()
},
success: function(addedResults) {
console.log(addedResults);
}
});
});
为了测试,请从PHP取回标题
if(isset($_POST['add_project_call'])) {
$title = $_POST['title'];
$visible = $_POST['visible'];
echo $title;
}
我看到序列化将表单数据转换为字符串,但是如何访问PHP中的值?
谢谢,
更改javascript,例如:
$('#submit_project').click(function() {
var form_data = {};
$('#add_project_form').serializeArray().map(function(n){form_data[n.name] = n.value;});
$.ajax({
url: 'ajax_calls.php',
type: 'POST',
data: {
add_project_call: true,
form_data: form_data
},
success: function(addedResults) {
console.log(addedResults);
}
});
});
更改php文件(ajax_calls.php),如下所示:
if(isset($_POST['add_project_call'])) {
$title = $_POST['form_data']['title'];
$visible = $_POST['form_data']['visible'];
echo $title;
}
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