[英]Use jQuery and ajax to send serialized form as value in data object to php
消除這個問題,我想通過數據對象中的AJAX將序列化的表單字符串發送給PHP。 我的表格是:
<form id="add_project_form" method="post">
<div class="form_group">
<p>Title:</p>
<input type="text" name="title">
</div>
<div class="form_group form_select" id="visible">
<p>Visible:
<select name="visible">
<option>1</option>
<option>0</option>
</select>
</p>
</div>
<a href="javascript:void(0)" id="submit_project">Add Project</a>
</form>
我可以像數據那樣做:$('form')。serialize(),但似乎無法在對象中傳遞它。
$('#submit_project').click(function() {
$.ajax({
url: 'ajax_calls.php',
type: 'POST',
data: {
add_project_call: true,
form_data: $('#add_project_form').serialize()
},
success: function(addedResults) {
console.log(addedResults);
}
});
});
為了測試,請從PHP取回標題
if(isset($_POST['add_project_call'])) {
$title = $_POST['title'];
$visible = $_POST['visible'];
echo $title;
}
我看到序列化將表單數據轉換為字符串,但是如何訪問PHP中的值?
謝謝,
更改javascript,例如:
$('#submit_project').click(function() {
var form_data = {};
$('#add_project_form').serializeArray().map(function(n){form_data[n.name] = n.value;});
$.ajax({
url: 'ajax_calls.php',
type: 'POST',
data: {
add_project_call: true,
form_data: form_data
},
success: function(addedResults) {
console.log(addedResults);
}
});
});
更改php文件(ajax_calls.php),如下所示:
if(isset($_POST['add_project_call'])) {
$title = $_POST['form_data']['title'];
$visible = $_POST['form_data']['visible'];
echo $title;
}
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