如何使用bash将多行合并为一行？

Question

所以我有这样的代码：

else if(between(pay,1260,1280))
{
    return 159;
}
else if(between(pay,1280,1300))
{
    return 162;
}
else if(between(pay,1300,1320))
{
    return 165;
}

但我希望它看起来像这样：

else if(between(pay,1260,1280)){return 159;}
else if(between(pay,1280,1300)){return 162;}
else if(between(pay,1300,1320)){return 165;}

我可以用bash做到吗？ 如果没有，我可以使用哪种语言？

完整的代码超过30,000行，我可以手动完成，但是我知道有更好的方法。 我想说的是'sed'命令可以帮助我使用正则表达式，但是据我所知。

附注：请忽略这只是一次未优化的过程。

Answer 1

这可能对您有用（GNU sed）：

sed '/^else/{:a;N;/^}/M!ba;s/\n\s*//g}' file

在模式空间中收集所需的行，并在遇到结束标记时删除所有换行和后面的空格，即一行的开始} 。

Answer 2

跟随awk也可能会帮助您。

awk -v RS="" '{
$1=$1;
gsub(/ { /,"{");
gsub(/ }/,"}");
gsub(/}/,"&\n");
gsub(/ else/,"else");
sub(/\n$/,"")
}
1
'  Input_file

输出如下。

else if(between(pay,1260,1280)){return 159;}
else if(between(pay,1280,1300)){return 162;}
else if(between(pay,1300,1320)){return 165;}

编辑：现在也添加解决方案的说明。

awk -v RS="" '{      ##Making RS(record separator) as NULL here.
$1=$1;               ##re-creating first field to remove new lines or space.
gsub(/ { /,"{");     ##globally substituting space { with only { here.
gsub(/ }/,"}");      ##globally substituting space } with only } here.
gsub(/}/,"&\n");     ##globally substituting } with } and new line here.
gsub(/ else/,"else");##globally substituting space else with only else here.
sub(/\n$/,"")        ##substituting new line at last of line with NULL.
}
1                    ##motioning 1 here as awk works on method of condition and action.
                     ##So here I am making condition as TRUE and then not mentioning any action so be default print of current line will happen.
'  Input_file