[英]Compare two files with awk - check if values from two columns in file1 are included somewhere in two columns in file2
[英]awk - Compare columns from two files and replace text in first file
我有两个文件。 第一列有1列,第二列有3列。 我想比较两个文件的第一列。 如果有巧合,则将第2列和第3列替换为特定值。 如果不是,则打印同一行。
文件1:
$ cat file1
26
28
30
档案2:
$ cat file2
1,a,0
2,a,0
22,a,0
23,a,0
24,a,0
25,a,0
26,r,1510139756
27,a,0
28,r,1510244156
29,a,0
30,r,1510157364
31,a,0
32,a,0
33,r,1510276164
34,a,0
40,a,0
所需的输出:
$ cat file2
1,a,0
2,a,0
22,a,0
23,a,0
24,a,0
25,a,0
26,a,0
27,a,0
28,a,0
29,a,0
30,a,0
31,a,0
32,a,0
33,r,1510276164
34,a,0
40,a,0
我正在使用gawk
来执行此操作(它在shell脚本中,并且正在使用solaris
),但是我无法正确输出输出。 它只打印匹配的行:
$fuente="file2"
gawk -v fuente="$fuente" 'FNR==NR{a[FNR]=$1; next}{print $1,$2="a",$3="0" }' $fuente file1 > file3
我得到的输出:
$ cat file3
26 a 0
28 a 0
30 a 0
为清晰起见,已真正展开; 叫做(fuente.awk)像这样:
awk -F \, -v fuente=file1 -f fuente.awk file2 # -F == IFS
BEGIN {
OFS="," # set OFS to make printing easier
while (getline x < fuente > 0) # safe way; read file into array
{
a[++i]=x # stuff indexed array
}
}
{ # For each line in file2
for (k=1 ; k<=i ; k++) # Lop over array (elements in file1)
{
if (($1==a[k]) && (! flag))
{
print($1,"a",0) # Found print new line
flag=1 # print only once
}
}
if (! flag) # Not found
{
print($0) # print original
}
flag=0 # reset flag
}
END { }
awk 单线 :
awk 'NR==FNR{ a[$1]; next }$1 in a{ $2="a"; $3=0 }1' file1 FS=',' OFS=',' file2
输出:
1,a,0
2,a,0
22,a,0
23,a,0
24,a,0
25,a,0
26,a,0
27,a,0
28,a,0
29,a,0
30,a,0
31,a,0
32,a,0
33,r,1510276164
34,a,0
40,a,0
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