选择一条记录中条件为真的记录

Question

我需要从下表的行中选择cid，项目和所有者，其中cid /项目组合的一或多个行的所有者为1。

cid | project | phase | task | owner
-----------------------------------
1   | 1       | 1     | 1    | 1
1   | 1       | 1     | 2    | 2
1   | 1       | 1     | 3    | 2
2   | 1       | 1     | 1    | 1
2   | 1       | 1     | 2    | 1
3   | 1       | 1     | 3    | 2

我的输出表应如下所示：

cid | project | phase | task | owner
-----------------------------------
1   | 1       | 1     | 1    | 1
1   | 1       | 1     | 2    | 2
1   | 1       | 1     | 3    | 2
2   | 1       | 1     | 1    | 1
2   | 1       | 1     | 2    | 1

下面的查询是我想出的。 看来确实可以，但是我的信心很低。 查询是解决问题的有效方法吗？

select task1.cid, task1.project, task1.owner
from 
(select cid, project, owner from table) task1
right join 
(select distinct cid, project, owner from table where owner = 1) task2
on task1.cid = task2.cid and task1.project = task2.project

（我没有从示例输出中删除阶段和任务列，以便于比较。）

Answer 1

您可以简单地使用IN子句

  select cid, project, owner
  from table
  where cid in (select distinct id from table where owner = 1)

或带有子查询的内部联接

  select a.cid, a.project, a.owner
  from table a 
  INNER JOIN ( select distinct cid , project
        from table where owner = 1
  ) t on t.cid = a.cid and t.project = a.project