[英]Decode JSON Swift 4
有人可以告诉我代码有什么问题吗? 我正在尝试将服务器中的JSON解析为变量以存储值。 当我运行代码时,我没有任何错误。 当我在解码数据后执行打印(用户)时,它没有返回任何内容。 有人可以帮我解决这个问题吗?
这是我用来从服务器检索数据的代码。
guard let url = URL(string: "my-url") else { return }
let session = URLSession.shared
let task = session.dataTask(with: url) { (data, _, _) in
guard let data = data else { return }
do {
let user = try JSONDecoder().decode(User.self, from: data)
print(user)
} catch {}
}
task.resume()
服务器的JSON结果
{
"UserId": "55844ef7-3f05-4560-8b37-216df422ffb8",
"ContactsDto": [
{
"Id": null,
"UserId": null,
"FriendUserId": "e61d09f8-9aec-4035-b0be-c36abea2d82b",
"FirstName": null,
"LastName": null,
"Email": "",
"PhonePrefix": null,
"Phone": "54943597",
"InviteStatus": "pending",
"UserStatus": null,
"ErrorCode": 0,
"ErrorMessage": null
},
{
"Id": null,
"UserId": null,
"FriendUserId": "b2e0d6d7-d97c-475e-a2ab-71cb8091a7a0",
"FirstName": null,
"LastName": null,
"Email": "",
"PhonePrefix": null,
"Phone": "207-7575",
"InviteStatus": "pending",
"UserStatus": null,
"ErrorCode": 0,
"ErrorMessage": null
},
{
"Id": null,
"UserId": null,
"FriendUserId": "8f8d6061-3a69-4641-ac40-329a824ff4e1",
"FirstName": null,
"LastName": null,
"Email": "",
"PhonePrefix": null,
"Phone": "58511968",
"InviteStatus": "pending",
"UserStatus": null,
"ErrorCode": 0,
"ErrorMessage": null
},
{
"Id": null,
"UserId": null,
"FriendUserId": "40c1e461-eb98-4e18-9363-13cfa460fe7e",
"FirstName": null,
"LastName": null,
"Email": "",
"PhonePrefix": null,
"Phone": "57864550",
"InviteStatus": "accepted",
"UserStatus": null,
"ErrorCode": 0,
"ErrorMessage": null
}
],
"ErrorCode": 0,
"ErrorMessage": null
}
我的结构
struct User: Decodable {
let UserId: String?
let ContactsDto: [ContactsDto]?
let ErrorCode: Int?
let ErrorMessage: String?
}
struct ContactsDto : Decodable {
let Id : String?
let UserId : String?
let FriendUserId : String?
let FirstName : String?
let LastName : String?
let Email : String?
let PhonePrefix : String?
let Phone : String?
let InviteStatus : String?
let UserStatus : String?
let ErrorCode : String?
let ErrorMessage : String?
}
通过查看代码,您尝试解码JSON的方式不正确。
您不会返回一个User数组,而是一个User Object。
因此,您可以尝试以下操作:
let user = try! JSONDecoder().decode(User.self, from: data)
根据您的错误,并且正如Josh在评论中告诉您的那样,模型上的类型不正确。
例如,您的ContactDto对象之一是:
{
"Id": null,
"UserId": null,
"FriendUserId": "e61d09f8-9aec-4035-b0be-c36abea2d82b",
"FirstName": null,
"LastName": null,
"Email": "",
"PhonePrefix": null,
"Phone": "54943597",
"InviteStatus": "pending",
"UserStatus": null,
"ErrorCode": 0,
"ErrorMessage": null
},
ErrorCode
类型是数字(看起来像整数),但是在您的模型结构中是String?。
请检查每个字段以获取所有类型,然后修复模型并重试。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.