弹簧数据jpa和多次收集的条件

Question

我想传递一个列表，其中所有应该匹配。

  @Query("select g.name as name FROM Gym  g  " +
            "LEFT JOIN g.listOfEquipment   listOfEquipment  " +
            "WHERE " +
            "(((:listOfEquipment) is null) or listOfEquipment.id in (:listOfEquipment)) "+
            "AND (((:listOfAmenity) is null) or listOfAmenity.id in (:listOfAmenity))")
  Page<Map<String, Object>> listing(@Param("listOfEquipment") Set<Integer> listOfEquipment,@Param("listOfAmenity") Set<Integer> listOfAmenity)

以上查询为OR工作，但我需要AND

假设我正在通过1,2,3那么结果应该是所有gym设备1 and 2 and 3同样的舒适性

我尝试使用包含jpql的给定集合的所有元素的集合查找项目

但它没有帮助我，因为有多个过滤器

网址是

http://localhost:8080/filter?listOfEquipment=5,3&listOfAmenity=51,13&sort=name

Answer 1

假设列表不包含重复项，此查询应该为您Gym.id匹配所有listOfEquipment

select g.id as name 
FROM Gym  g 
LEFT JOIN g.listOfEquipment listOfEquipment
WHERE listOfEquipment.id in (:listOfEquipment)) 
GROUP BY g.id
HAVING count(g.id) = #{#listOfEquipment.size}    

您可以使用它和listOfAmenity的类似查询作为主查询中的子选择。

select g.name as name 
FROM Gym  g 
LEFT JOIN g.listOfEquipment listOfEquipment 
WHERE (((:listOfEquipment) is null) 
    OR g.id in (
    select g.id as name 
    FROM Gym  g 
    LEFT JOIN g.listOfEquipment listOfEquipment
    WHERE listOfEquipment.id in (:listOfEquipment)) 
    GROUP BY g.id
    HAVING count(g.id) = #{#listOfEquipment.size}   
)) 
AND (((:listOfAmenity) is null) 
    OR g.id in (
    select g.id as name 
    FROM Gym  g 
    LEFT JOIN g.listOfAmenity listOfAmenity
    WHERE listOfAmenity.id in (:listOfAmenity)) 
    GROUP BY g.id
    HAVING count(g.id) = #{#listOfAmenity.size}   
))

Answer 2

在最后的AND条件中有一个缺少的括号，它应该如下

@Query("select g.name as name FROM Gym  g  " +
        "LEFT JOIN g.listOfEquipment   listOfEquipment  " +
        "WHERE " +
        "(((:listOfEquipment) is null) or listOfEquipment.id in        (:listOfEquipment)) "+
        "AND (((:listOfAmenity) is null) or listOfAmenity.id in (:listOfAmenity))")