从列表python添加类似的字母数字元素

Question

我有两个列表A = ['1a', '3c']和B = ['2a', '1b'] 。 我想添加以相同字符结尾的字符串，并更新A的内容，如下所示：

最终结果为： A = ['3a', '3c'] 。 下面是我的代码：

for x, y in enumerate(A):
        # gets the indices of B which has same end character
        l = [B.index(i) for i in B if y[1] in i] 

Answer 1

您可以使用正则表达式从char中拆分int，然后将它们相等，然后用list comp求和（考虑两个列表的len等于）：

汇入

A = ['1a', '3c', "2b"]
B = ['2a', '1b', "4c"]

def splitNum(x):
  return list(filter(None, re.split(r'(\d+)', x)))

A = [str(int(splitNum(x)[0]) + int(splitNum(y)[0])) + (splitNum(x)[1]) for x in A for y in B if splitNum(x)[1] == splitNum(y)[1]]

print(A)

 => ['3a', '7c', '3b']

Answer 2

尝试这样的事情：

A = ['1a', '3c'] 
B = ['2a', '1b']
for i, (x, y) in enumerate(zip(A, B)):
  if x[-1] == y[-1]:
    A[i] = str(int(x[0])+int(y[0])) + x[-1]
print A