[英]JPA - query parameter is null
@Query("select users from User users " +
"where users.id like concat('%',?1,'%') and " +
"users.name like concat('%',?2,'%') and " +
"users.telNo like concat('%',?3,'%') ")
List<User> fuzzyQueryUser(Integer id, String name, String telNo);
当第一个参数id
为null时,模糊查询没有结果。 如果参数为null,我希望在数据库中有类似的条目时得到结果。 我该怎么办? 谢谢。
@Query("select users from User users " +
"where (users.id like concat('%',?1,'%') or ?1 is null or ?1 ='')and " +
"(users.name like concat('%',?2,'%') or ?2 is null or ?2 ='') and " +
"(users.telNo like concat('%',?3,'%') or ?3 is null or ?3 ='')")
List<User> fuzzyQueryUser(String id, String name, String telNo);
像这样
@Query("select users from User users " +
"where (users.id like concat('%',?1,'%') or ?1 is null )and " +
"(users.name like concat('%',?2,'%') or ?2 is null or ?2 ='') and " +
"(users.telNo like concat('%',?3,'%') or ?3 is null or ?3 ='')")
List<User> fuzzyQueryUser(Integer id, String name, String telNo);
只需添加另一个条件来忽略null和可选的空字符串:
@Query("select users from User users " +
"where (users.id like concat('%',?1,'%') or ?1 is null) and "
+"users.name like concat('%',?2,'%') and " +
"users.telNo like concat('%',?3,'%') ")
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